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liraira [26]
3 years ago
10

Find the value of a that makes the following equation true for all values of x 0.9^60x=a^x

Mathematics
2 answers:
Sindrei [870]3 years ago
8 0

Answer:

A

Step-by-step explanation:

(A) would be correct.

A^x would yield (0.9^60)^x when plugged in. Since an exponent

on the parenthesis surrounding a number with an exponent already

just gets multiplied to the number's exponent, we'd end up with

      0.9^60*x , which is the same as the given example.

MrRissso [65]3 years ago
7 0

Step-by-step explanation:

I am new to brainly plz help me bro

thank u

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For \pi, we expect \cos\theta. Then recalling that \sin^2\theta+\cos^2\theta=1, we have

\cos\theta=-\sqrt{1-\sin^2\theta}=-\dfrac12

Then by definition of tangent,

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4 years ago
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A pizza had 9/10 left before Lucas ate 4/5 of the pizza. How much pizza is left over
Norma-Jean [14]
1/10 is left.

Explanation:

First we need to find a common denominator. Since 5×2=10, if we multiply 4/5 by 2/2, we will be able to subtract that from 9/10.

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3 years ago
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The Pirerras are planning to go to Europe 3 years from now and have agreed to set aside $140/month for their trip. If they depos
Natalka [10]

Answer:

(a)$5805.21

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Step-by-step explanation:

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F.V.=\dfrac{P[(1+i)^{kn}-1]}{i}

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(b)For the Johnsons, Present value of Mortgage is derived using the formula:

\Text{Present Lump Sum}, A_0=\dfrac{P[1-(1+i)^{-kt}]}{\frac{r}{k} }

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\Text{Present Lump Sum}, A_0=\dfrac{1000[1-(1+\frac{0.08}{12} )^{-12*15}]}{\frac{0.08}{12} }=\$104640.59

Adding  a down payment of $16000

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At $1300 Monthly Payment

\Text{Present Lump Sum}, A_0=\dfrac{1300[1-(1+\frac{0.08}{12} )^{-12*15}]}{\frac{0.08}{12} }=\$136032.77

Adding  a down payment of $16000

  • Most Expensive Mortgage = 136032.77+16000=$152032.77
4 0
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Ulleksa [173]

Answer:

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Answer:

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