This is not a polynomial equation unless one of those is squared. As it stands x=-.833. If you can tell me which is squared I can help solve the polynomial.
Ok, that is usually notated as x^3 to be clear. I'll solve it now.
x^3-13x-12=0
Then use factor theorum to solve x^3-13x-12/x+1 =0
So you get one solution of x+1=0
x=-1
Then you have x^2-x-12 now you complete the square.
Take half of the x-term coefficient and square it. Add this value to both sides. In this example we have:
The x-term coefficient = −1
The half of the x-term coefficient = −1/2
After squaring we have (−1/2)2=1/4
When we add 1/4 to both sides we have:
x2−x+1/4=12+1/4
STEP 3: Simplify right side
x2−x+1/4=49/4
STEP 4: Write the perfect square on the left.
<span>(x−1/2)2=<span>49/4
</span></span>
STEP 5: Take the square root of both sides.
x−1/2=±√49/4
STEP 6: Solve for x.
<span>x=1/2±</span>√49/4
that is,
<span>x1=−3</span>
<span>x2=4</span>
<span>and the one from before </span>
<span>x=-1</span>
Answer:0.45
Step-by-step explanation
Divide 5.40 by 12 and it gives you 0.45
3(2x - 1) - 2(3x + 4) = 11x
- Distribute 3 inside the parentheses.
6x - 3 - 2(3x + 4) = 11x
- Distribute 2 inside the parentheses.
6x - 3 - 6x - 8 = 11x
-11 = 11x
<h3>x = -1</h3>
Discrete data<span> is information that can be categorized into a classification. </span>Discrete data<span> is based on counts. Only a finite number of values is possible, and the values cannot be subdivided meaningfully. For example, the number of parts damaged in shipment.
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Answer:
A is correct
Step-by-step explanation:
What we need to do here is to multiply all the roots together
The roots are;
3, √5 and -√5
Let’s have them in form of a sum
if x = 3, then the root is x-3
If x = √5, then the root is x-√5
If x = -√5, then the root is x+ √5
Now we need to multiply all these together to arrive at the original polynomial
Let’s start by using the roots
(x-√5)(x+ √5)
we can use the difference of 2 squares here and we arrive at (x^2 -5)
So finally, the polynomial would be;
(x^2-5)(x-3)
= x(x^2-5) -3(x^2-5)
= x^3-5x-3x^2+15
By rearranging, we have;
x^3-3x^2-5x+15
