Answer:
the largest angle of the field is 149⁰
Step-by-step explanation:
Given;
perimeter of the triangular filed, P = 120 m
length of two known sides, a and b = 21 m and 40 m respectively
The length of the third side is calculated as follows;
a + b + c = P
21 m + 40 m + c = 120 m
61 m + c = 120 m
c = 120 m - 61 m
c = 59 m
B
↓ ↓
↓ ↓
↓ ↓
A → → → → → → → → → → → C
Consider ABC as the triangular field;
Angle A is calculated by applying cosine rule;

Angle B is calculated as follows;

Angle C is calculated as follows;

Therefore, the largest angle of the field is 149⁰.
(f o h) = -(x - 3/3) - 1
(f o h) = (-x + 3)/3 - 1
(f o h)(1) = (-1 + 3)/3 - 1
(f o h)(1) = 2/3 - 1
(f o h)(1) = -1/3
I believe the answer is C - 60 inches. 60 x 2 = 120, which is both lengths, and since he width is half the length, then 30 x 2 = 60. So 130 (length) + 60 (width) = 180. So 60 inches would be the maximum length for both sides.
Answer:
Angle 1 is = 54° ( vertically opposite angles)
Angle 2 is = Angle 1 (corresponding angles are equal)
therefore Angle 2 = 54°
The answer is 1 and I’m sure about that