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3 years ago

(8r2 -12r +4) - (3r2 + 5r -1)

Mathematics

1 answer:

Ivan3 years ago

7 0

Answer 5r^ 2 −17r+5

Step-by-step explanation:

Changes made to your input should not affect the solution:

(1): "r2" was replaced by "r^2". 1 more similar replacement(s).

STEP

Equation at the end of step 1

(((8•(r2))-12r)+4)-((3r2+5r)-1)

STEP

Equation at the end of step

((23r2 - 12r) + 4) - (3r2 + 5r - 1)

STEP

Trying to factor by splitting the middle term

3.1 Factoring 5r2-17r+5

The first term is, 5r2 its coefficient is 5 .

The middle term is, -17r its coefficient is -17 .

The last term, "the constant", is +5

Step-1 : Multiply the coefficient of the first term by the constant 5 • 5 = 25

Step-2 : Find two factors of 25 whose sum equals the coefficient of the middle term, which is -17 .

-25 + -1 = -26

-5 + -5 = -10

-1 + -25 = -26

1 + 25 = 26

5 + 5 = 10

25 + 1 = 26

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Final result :

5r^2 - 17r + 5

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Find the value of w<br> A. 141<br> B. 110<br> C. 80<br> D. 100

saw5 [17]

Answer:

141

Step-by-step explanation:

Angle Formed by Two Chords= 1/2(SUM of Intercepted Arcs)

We know z+70 = 180 since they form a straight line

z = 110

z = 1/2 ( 79+w)

110 = 1/2 ( 79+w)

220 = 79+w

220-79 = w

141 =w

5 0

3 years ago

HELPP!!

SSSSS [86.1K]

Answer:

There are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.

Step-by-step explanation:

This can be obtained by after a simple counting of number from 2020 and 2400 as follows:

The first set of integers are:

2345, 2346, 2347, 2348, and 2349.

Therefore, there are 6 integers in first set.

The second set of integers are:

2356, 2357, 2358, and 2359.

Therefore, there are 4 integers in second set.

The third set of integers are:

2367, 2368, and 2369.

Therefore, there are 3 integers in third set.

The fourth set of integers are:

2378, and 2379.

Therefore, there are 2 integers in fourth set.

The fifth and the last set of integer is:

2389

Therefore, there is only 1 integers in fifth set.

Adding all the integers from each of the set above, we have:

Total number of integers = 6 + 4 + 3 + 2 + 1 = 15

Therefore, there are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.

7 0

3 years ago

Can u please have help i cant get this

adell [148]

Answer:

Step-by-step explanation:

Three or more points that lie on the same line are collinear points.

I have highlighted the points so you can see where they lay on the lines. You can see only one set of points is on 2 different lines.

Please mark Brainliest when able.

7 0

3 years ago

I’m confused and don’t have an angle tool to even try to do the question

yanalaym [24]

<h3>Answer: 40</h3>

=================================================

Explanation:

JQ is longer than QN. We can see this visually, but the rule for something like this is the segment from the vertex to the centroid is longer compared to the segment that spans from the centroid to the midpoint.

See the diagram below.

The ratio of these two lengths is 2:1, meaning that JQ is twice as long compared to QN. This is one property of the segments that form when we construct the centroid (recall that the centroid is the intersection of the medians)

We know that JN = 60

Let x = JQ and y = QN

The ratio of x to y is x/y and this is 2/1

x/y = 2/1

1*x = y*2

x = 2y

Now use the segment addition postulate

JQ + QN = JN

x + y = 60

2y + y = 60

3y = 60

y = 60/3

y = 20

QN = 20

JQ = 2*y = 2*QN = 2*20 = 40

--------------

We have

JQ = 40 and QN = 20

We see that JQ is twice as larger as QN and that JQ + QN is equal to 60.

7 0

3 years ago

Part A

Deffense [45]

Answer: Not safe

Step-by-step explanation:

Let the angle of elevation of the ramp be θ, then:

$\begin{aligned}&\sin \theta=\frac{1.5}{10}=0.15 \\&\theta=\sin ^{-1}(0.15) \approx 8.63^{\circ}\end{aligned}$

But the maximum angle for the ramp cannot exceed 7.1°. The calculated angle of elevation will make it difficult, if not impossible, for motorized wheelchairs to get up the ramp.

Therefore, the ramp at the local library is not safe for motorized wheelchairs

5 0

2 years ago