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3 years ago

What is the resulting ordered pair if the value of the independent variable is 2?

1 answer:

5 0

To find f(2), put 2 where the variable is, then do the arithmetic. It might be easier to factor out x^2:
f(x) = (-6x-4)·x^2
f(2) = (-6·2-4)·2^2
= -16·4
= -64

Then the ordered pair (x, f(x)) for x=2 is
B. (2, -64)

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Pierre is running 26 and 2/10 miles in the marathon. He has run 3/4 of the way. How far has he run?

Harman [31]

Pierre ran 19 and 13/20 miles.

Given:
marathon length : 26 2/10 miles
pierre's length ran : 3/4 of the way.

Multiply the fractions.
Convert the marathon length from a mixed fraction into a fraction.
26 2/10 = ((26*10)+2)/10 = (260+2)/10 = 262/10

262/10 * 3/4 = (262*3) / (10*4) = 786/40 = 19 26/40

19 26/40 simplified to 19 13/20 miles

26 ÷ 2 = 13
40 ÷ 2 = 20

3 0

3 years ago

The weights of a certain dog breed are approximately normally distributed with a mean of 49 pounds, and a standard deviation of

AlekseyPX

Answer:

a. 74.86%

b. 50%

c. 50%

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with a mean of 49 pounds, and a standard deviation of 6 pounds.

This means that $\mu = 49, \sigma = 6$

a. Find the percentage of dogs of this breed that weigh less than 53 pounds.

The proportion is the p-value of Z when X = 53. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{53 - 49}{6}$

$Z = 0.67$

$Z = 0.67$ has a p-value of 0.7486.

0.7486*100% = 74.86%, which is percentage of dogs of this breed that weigh less than 53 pounds.

b. Find the percentage of dogs of this breed that weigh less than 49 pounds.

p-value of Z when X = 49, so:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{49 - 49}{6}$

$Z = 0$

$Z = 0$ has a p-value of 0.5

0.5 = 50% of dogs of this breed that weigh less than 49 pounds.

c. Find the percentage of dogs of this breed that weigh more than 49 pounds.

1 subtracted by the p-value of Z when X = 49, so:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{49 - 49}{6}$

$Z = 0$

$Z = 0$ has a p-value of 0.5.

1 - 0.5 = 0.5 = 50% of dogs of this breed that weigh more than 49 pounds.

8 0

3 years ago

A box of cereal states that there are 87 calories in a 3/4 -cup serving. What is the unit rate for calories per cup? How many

mash [69]

Answer:

261

Step-by-step explanation:

In 1 is 65.25, in 4 is 261. Dm me if I'm wrong. Please mark as brainliest

6 0

3 years ago

Please please help me out

IgorLugansk [536]

So first we have to convert feet o inches right?
Imfeet is 12inches.
So I side is 12by 12 which is 144.
There are 6 sides so 144 by 6.
And th answer is 864.
Alternatively you can calculate the entire are in inches first and then convert it.

6 0

3 years ago

3p^2-2p-5 factor completely

fiasKO [112]

$a x^{2} +bx+c$ Here is the basis equation. $3p ^{2} -2p-5$ Let us use the AC method. Multiple the A and C values, or 3 and -5. This is -15. So now ask yourself... what multiplies to -15 but adds to -2. that would be, -5 and 3. So now reconstruct your equation ... $(3p^2+3p)+(-5p-5)$ The larger number will go first (3>-5) Now you can factor each group. $3p(p+1)-5(p+1)$ Because what is now in the parentheses are qualm and they are being added, you can now make the coeffecients a group $(3p-5) (p+1)$ If you are solving for p, set equal to zero and then the answers are -1 and (5/3). If you are just factoring, then that is your answer.

7 0

3 years ago

Read 2 more answers