28-8 is the discount price of each ticket, and the (28-8) is equal to (=) -----> 24(28-8
Step-by-step explanation:
that is the answer
As the ball hits the ground, its height will be equal to 0, so...
-3t² + 12t + 63 = 0
t² - 4t - 21 = 0
Using the Viet's theorem to solve the quadratic equation quicker:
t₁ + t₂ = 4
t₁t₂ = -21
t₁ = -3 - this is not possible because time can't be negative
t₂ = 7
That means, the ball is expected to hit the ground after 7 sec has passed.
Answer:
6/8 of a mile,
Step-by-step explanation:
if one furlong is 1/8 of a mile, the 6 shall be 1/8 added to itself 6 times, therefore it shall be 6/8.
a) You are told the function is quadratic, so you can write cost (c) in terms of speed (s) as
... c = k·s² + m·s + n
Filling in the given values gives three equations in k, m, and n.

Subtracting each equation from the one after gives

Subtracting the first of these equations from the second gives

Using the next previous equation, we can find m.

Then from the first equation
[tex]28=100\cdot 0.01+10\cdot (-1)+n\\\\n=37[tex]
There are a variety of other ways the equation can be found or the system of equations solved. Any way you do it, you should end with
... c = 0.01s² - s + 37
b) At 150 kph, the cost is predicted to be
... c = 0.01·150² -150 +37 = 112 . . . cents/km
c) The graph shows you need to maintain speed between 40 and 60 kph to keep cost at or below 13 cents/km.
d) The graph has a minimum at 12 cents per km. This model predicts it is not possible to spend only 10 cents per km.
- 6+t=6+t
- y+11
- 12-4=8
- 7/t
- 25-19=6
- 2s+s
- 11-r
- 2s+6x
- x/17-(12+2)
- 3+(x-10)
- (7+2)/2
- x-13
Hope this helps and have a BLESSED DAY! I also put some charts with my answer to help you better understand it!
-Cutiepatutie :-)