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iragen [17]
3 years ago
12

in examination of 300 full marks, a student secured 110 marks and failed by 10 marks. what is the pass percent?​

Mathematics
1 answer:
pishuonlain [190]3 years ago
5 0

Answer:

36.67 %

Step-by-step explanation:

Pass mark = 110 marks

Total mark = 300 marks

Pass percentage=

\frac{pass \: mark}{pass \: percentage}  \times 100

Substitute values into the equation

\frac{110}{300}  \times 100

Cross cancel common factor: 100

\frac{110}{3}  = 36  \frac{2}{3}   \% \: or \: 36.67 \%

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The school is planning a field trip to the science center. Tickets are originally $28, but school
Agata [3.3K]

28-8 is the discount price of each ticket, and the (28-8) is equal to (=) -----> 24(28-8

Step-by-step explanation:

that is the answer

4 0
2 years ago
The function h ( t ) = − 3t 2 + 12 t + 63 models the flight of a ball t seconds after it is thrown. When can the ball be expecte
Oksana_A [137]

As the ball hits the ground, its height will be equal to 0, so...

-3t² + 12t + 63 = 0

t² - 4t - 21 = 0

Using the Viet's theorem to solve the quadratic equation quicker:

t₁ + t₂ = 4

t₁t₂ = -21

t₁ = -3 - this is not possible because time can't be negative

t₂ = 7

That means, the ball is expected to hit the ground after 7 sec has passed.

4 0
3 years ago
1) A furlong is 1/8 of a mile. What part of a mile is 6 furlongs?
Semmy [17]

Answer:

6/8 of a mile,

Step-by-step explanation:

if one furlong is 1/8 of a mile, the 6 shall be 1/8 added to itself 6 times, therefore it shall be 6/8.

5 0
3 years ago
Read 2 more answers
How would you do a,b,c,and d
I am Lyosha [343]

a) You are told the function is quadratic, so you can write cost (c) in terms of speed (s) as

... c = k·s² + m·s + n

Filling in the given values gives three equations in k, m, and n.

28 = k\cdot 10^2+m\cdot 10+n\\21=k\cdot 20^2+m\cdot 20+n\\16=k\cdot 30^2+m\cdot 30+n

Subtracting each equation from the one after gives

-7=300k+10m\\-5=500k+10m

Subtracting the first of these equations from the second gives

2=200k\\\\k=\dfrac{2}{200}=0.01

Using the next previous equation, we can find m.

-5=500\cdot 0.01+10m\\\\m=\dfrac{-10}{10}=-1

Then from the first equation

[tex]28=100\cdot 0.01+10\cdot (-1)+n\\\\n=37[tex]

There are a variety of other ways the equation can be found or the system of equations solved. Any way you do it, you should end with

... c = 0.01s² - s + 37

b) At 150 kph, the cost is predicted to be

... c = 0.01·150² -150 +37 = 112 . . . cents/km

c) The graph shows you need to maintain speed between 40 and 60 kph to keep cost at or below 13 cents/km.

d) The graph has a minimum at 12 cents per km. This model predicts it is not possible to spend only 10 cents per km.

4 0
3 years ago
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Klio2033 [76]
  1. 6+t=6+t
  2. y+11
  3. 12-4=8
  4. 7/t
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Hope this helps and have a BLESSED DAY! I also put some charts with my answer to help you better understand it!

-Cutiepatutie :-)

8 0
3 years ago
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