Please help I will help you you can help me and I help you 1. Why must Lincoln Douglas treat each resolution independently to determine
burdens/values?
First I hope you those mask you can do math I will help you toAnswer is 40 524-678 9 10 into the answer of your math question you have to ask your math teacher Mr. Philip Sims
Its the last option because anything between 0 to 1 would he smaller than the original
The volume of a gas in a container varies inversely with the pressure on the gas. If a gas has a volume of <span>250 </span>cubic inches under a pressure of<span>
</span><span>4 </span>pounds per square inch, what will be its volume if the pressure is increased to 20 pounds per square inch? (Round off your answer to the nearest cubic inch.)
Answer:
Are we human, or are we dancer
Step-by-step explanation: this is an answer your teacher would love trust me ;)
Answer:
x = -1
x = 5
Step-by-step explanation:
Use pythagorean theorem: a² + b² = c²
x² + (2x + 2)² = (2x + 3)²
Since these are quantities, you'll have to make them into quadratic equations.
(2x + 2)(2x + 2) = 4x² + 4x + 4x + 4
(2x + 3)(2x + 3) = 4x² + 6x + 6x + 9
x² + 4x² + 4x + 4x + 4 = 4x² + 6x + 6x + 9
Combine like terms
5x² + 8x + 4 = 4x² + 12x + 9
Move one side to set the equation equal to 0
x² - 4x - 5 = 0
Solve
x² - 5x + x - 5 = 0
x(x - 5) + 1(x - 5) = 0
(x + 1)(x - 5) = 0
x = -1, 5
<em>We</em><em> </em><em>can</em><em> </em><em>check</em><em> </em><em>that</em><em> </em><em>these</em><em> </em><em>are</em><em> </em><em>correct</em><em> </em><em>by</em><em> </em><em>plugging</em><em> </em><em>them</em><em> </em><em>in</em><em> </em><em>for</em><em> </em><em>x</em><em> </em><em>and</em><em> </em><em>seeing</em><em> </em><em>if</em><em> </em><em>they</em><em> </em><em>are</em><em> </em><em>equal</em>
<em>For</em><em> </em><em>example</em>
<em>(</em><em>-1</em><em>)</em><em>²</em><em> </em><em>+</em><em> </em><em>(</em><em>2</em><em>(</em><em>-1</em><em>)</em><em> </em><em>+</em><em> </em><em>2</em><em>)</em><em>²</em><em> </em><em>=</em><em> </em><em>(</em><em>2</em><em>(</em><em>-1</em><em>)</em><em> </em><em>+</em><em> </em><em>3</em><em>)</em><em>²</em>
<em>1</em><em> </em><em>=</em><em> </em><em>1</em>
