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lisov135 [29]
3 years ago
6

(PLEASE!!!!) The congruency of MNO and XYZ can be proven using a reflection across the line bisecting OZ. However, this congruen

cy can also be proven using geometric postulates, theorems, and definitions. Prove that the triangles are congruent using a two-column proof and triangle congruency theorems.

Mathematics
2 answers:
jeka943 years ago
7 0

Hello! I had this same question on a test, so I am going to share the answers that I were told are 100% correct!

1: Given

2: Given

3: Given

4: Definition of congruence

5: Reflexive Property

6: Addition property

7: Segment addition postulate

8: Definition of congruence

9: AAS Congruency theorem

Of course, some tests are worded differently, so some extra reading is required. However, I hope this helps, good luck! :)

finlep [7]3 years ago
6 0

Explanation:

Only the reasons need be given here, as the statements are already given in your figure.

  1. Given
  2. Given
  3. Given
  4. Definition of congruent line segments
  5. Symmetric property of congruence
  6. Addition and substitution properties of equality*
  7. Segment addition theorem
  8. Definition of congruent line segments
  9. AAS congruence postulate

_____

* The addition property says if A=B, then A+C=B+C. The substitution property further says if C=D, then A+C=B+D (D can be substituted for C). IMO, both properties are needed together to get from A=B and C=D to A+B=C+D.

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Troyanec [42]
The tree diagram of the problem above is attached
There are four outcomes of the two events,

First test - Cancer, Second Test - Cancer, the probability is 0.0396
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3 years ago
Explanation of Baye's theorem.
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I will be including both an basic explanation of what it is and its proof.

I'm guessing you are either learning about conditional probability at school or preparing for competitions.

Baye's theorem states:

P(A|B)=\frac{P(B|A)P(A)}{P(B)}

That is the theorem itself and it means that the probability that event A happens given B is true equals the probability event B happens given A is true times the probability event A happens divided by the probability B happens.

That was the basic of the theorem and the proof of this is basically just testing how well you understand what conditional probability is.

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Now we know that the probably that A and B both happens is the same as the probably that B and A both happens.

Therefore P(A|B) can be seen as P(B|A) multiplied by P(A) and then divided by P(B) which gives the right hand side of the first equation. And this is basically the theorem.

P(A|B)=\frac{P(B|A)P(A)}{P(B)}

**Note P(B) have to be not equal to 0 because having a 0 in the denominator would make this equation undefined.

If you have any questions or need further explanations please ask me in the comments of the answer, I hope this helped!

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