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3 years ago

-17 = x/-3 for x. thanks for helping

Mathematics

2 answers:

Nonamiya [84]3 years ago

5 0

Answer:

x = 51

Step-by-step explanation:

-17 = x / -3

-17 * (-3) = x

-17 * (-3) = 51

x = 51

Check your work

-17 = 51 / (-3)

vekshin13 years ago

3 0

Answer:

-17 = x/-3 for x.

Step-by-step explanation:

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\large -6x+6y=6 \large 6x+3y=12

Kaylis [27]

Answer:

the solution of the system is:

x = 1 and y = 2.

Step-by-step explanation:

I suppose that we want to solve the equation:

-6*x + 6*y = 6

6*x + 3*y = 12

To solve this, we first need to isolate one of the variables in one of the equations.

Let's isolate y in the first equation:

6*y = 6 + 6*x

y = (6 + 6*x)/6

y = 6/6 + (6*x)/6

y = 1 + x

Now we can replace this in the other equation:

6*x + 3*(1 + x) = 12

6*x + 3 + 3*x = 12

9*x + 3 = 12

9*x = 12 - 3 = 9

x = 9/9 = 1

Now that we know that x = 1, we can replace this in the equation "y = 1 + x" to find the value of y.

y = 1 + (1) = 2

Then the solution of the system is:

x = 1 and y = 2.

6 0

3 years ago

Let f(x,y,z) = ztan-1(y2) i + z3ln(x2 + 1) j + z k. find the flux of f across the part of the paraboloid x2 + y2 + z = 3 that li

Sophie [7]

Consider the closed region $V$ bounded simultaneously by the paraboloid and plane, jointly denoted $S$ . By the divergence theorem,

$\displaystyle\iint_S\mathbf f(x,y,z)\cdot\mathrm dS=\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV$

And since we have

$\nabla\cdot\mathbf f(x,y,z)=1$

the volume integral will be much easier to compute. Converting to cylindrical coordinates, we have

$\displaystyle\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\iiint_V\mathrm dV$
$=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=2}^{z=3-r^2}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle2\pi\int_{r=0}^{r=1}r(3-r^2-2)\,\mathrm dr$
$=\dfrac\pi2$

Then the integral over the paraboloid would be the difference of the integral over the total surface and the integral over the disk. Denoting the disk by $D$ , we have

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-\iint_D\mathbf f\cdot\mathrm dS$

Parameterize $D$ by

$\mathbf s(u,v)=u\cos v\,\mathbf i+u\sin v\,\mathbf j+2\,\mathbf k$
$\implies\mathbf s_u\times\mathbf s_v=u\,\mathbf k$

which would give a unit normal vector of $\mathbf k$ . However, the divergence theorem requires that the closed surface $S$ be oriented with outward-pointing normal vectors, which means we should instead use $\mathbf s_v\times\mathbf s_u=-u\,\mathbf k$ .

Now,

$\displaystyle\iint_D\mathbf f\cdot\mathrm dS=\int_{u=0}^{u=1}\int_{v=0}^{v=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(-u\,\mathbf k)\,\mathrm dv\,\mathrm du$
$=\displaystyle-4\pi\int_{u=0}^{u=1}u\,\mathrm du$
$=-2\pi$

So, the flux over the paraboloid alone is

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-(-2\pi)=\dfrac{5\pi}2$

6 0

3 years ago

What equation can be used to find the length of AC

Leno4ka [110]

I'm pretty sure this is the answer:
(10)sin(40°) = AC

It's sin becasue it needs the opposite side of 40° and has the hypotenuse.

5 0

3 years ago

Help me, Ive got number 2 already

beks73 [17]

Answer:

1. is no

Step-by-step explanation: