Answer:
The perimeter of triangle PQR is 17 ft
Step-by-step explanation:
Consider the triangles PQR and STU
1. PQ ≅ ST = 4 ft (Given)
2. ∠PQR ≅ ∠STU (Given)
3. QR ≅ TU = 6 ft (Given)
Therefore, the two triangles are congruent by SAS postulate.
Now, from CPCTE, PR = SU. Therefore,

Now, side PR is given by plugging in 3 for 'y'.
PR = 3(3) - 2 = 9 - 2 = 7 ft
Now, perimeter of a triangle PQR is the sum of all of its sides.
Therefore, Perimeter = PQ + QR + PR
= (4 + 6 + 7) ft
= 17 ft
Hence, the perimeter of triangle PQR is 17 ft.
Answer:
64
Step-by-step explanation:
divide 2048 by 2 since half is already used gives you 1024 ...then divide 1024 by 16 to get 64..
3x+y=8
y=8-3x
5x+3(8-3x)=8
5x+24-9x=8
-4x+24=8
-4x=-16
x=4
5x+3y=8
5(4)+3y=8
20+3y=8
3y=-12
Y=-4
5x+3y=8
5(4)+3(-4)=8
20+-12=8
8=8
So u just do 27*0.45 to get 12.15 and subtract that to get 14.85