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3 years ago

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If an airplane was going 900 km/h and it traveled 675,000 m how long did it take to get to it's destination?

1 answer:

Juli2301 [7.4K]3 years ago

8 0

The answer: Time= Distance divide Speed.
Speed= 675,000 divide 900= 750 minutes. Convert that to hours and that leaves you with 12 hours and a half. If these questions are bothering you, just revise them- they’re speed distance time equations and i’d be blessed if they come up in my maths exam tomorrow.

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Answer:

A

Step-by-step explanation:

We are given:

$\displaystyle \cos(\theta)=-\frac{12}{13},\,\theta\in\text{QIII}$

Since cosine is the ratio of the adjacent side over the hypotenuse, this means that the opposite side is (we can ignore negatives for now):

$o=\sqrt{13^2-12^2}=\sqrt{25}=5$

So, the opposite side is 5, the adjacent side is 12, and the hypotenuse is 13.

And since θ is in QIII, sine/cosecant is negative, cosine/secant is negative, and tangent/cotangent is positive.

Cosecant is given by the hypotenuse over the opposite side. Thus:

$\displaystyle \csc(\theta)=\frac{13}{5}$

Since θ is in QIII, cosecant must be negative:

$\displaystyle \csc(\theta)=-\frac{13}{5}$

Our answer is A.

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