Changes made to your input should not affect the solution:
(1): "x1" was replaced by "x^1". 3 more similar replacement(s).
Step by step solution :
Step 1 :
Equation at the end of step 1 :
x + ((((3•19x2) • x6) • x8) • x12)
Step 2 :
Step 3 :
Pulling out like terms :
3.1 Pull out like factors :
57x28 + x = x • (57x27 + 1)
Trying to factor as a Sum of Cubes :
3.2 Factoring: 57x27 + 1
Theory : A sum of two perfect cubes, a3 + b3 can be factored into :
(a+b) • (a2-ab+b2)
Proof : (a+b) • (a2-ab+b2) =
a3-a2b+ab2+ba2-b2a+b3 =
a3+(a2b-ba2)+(ab2-b2a)+b3=
a3+0+0+b3=
a3+b3
Check : 57 is not a cube !!
Final result :
x • (57x27 + 1)
Processing ends successfully
Answer:
*Replace each "x" with the required numbers .
1) g (14) ; Ans;
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2) f (-8) ; Ans;
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3) j (3) ; Ans;
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4) h (4) ; Ans;
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5) f (2.8) ; Ans;
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6) j(-5) ; Ans;
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7) g(3/4); Ans;
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8) [h(6.2)]² ; Ans;
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9) j(2) + g(-3) ; Ans;
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10) h(1) - f(-10) ; Ans;
___________o____o__________
**We look at the table. If f(4) or f(-2) is required, it came from f(x) by substitution each x with the required numbers, and the result is in the table f(x) .
***But if he says that f(x) is equal to a number, he means the resulting table f(x) and asks for the "x" that you take from the table "x" .
<u>Table (1) Ans;</u>
f(4) = <u> –3</u>
f(-2) = <u>– 6</u>
If f(x)= -3 ,then x = <u>4</u>
If f(x) = 1 , then x = <u>3</u>
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<u>Table (2) Ans; </u>
f(4) = <u>–7</u>
f(-2) = <u>1</u>
If f(x)= -3 ,then x = <u>0</u>
If f(x) = 1 , then x = <u>- 2</u>
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<u>Table (3)Ans;</u>
f(4) = <u>7</u>
f(-2) = <u>3</u>
If f(x)= -3 ,then x = <u>6</u>
If f(x) = 1 , then x = <u>0</u>
I hope I helped you^_^
Answer:
the length of b is 7.56 centimeters.
Step-by-step explanation:
Answer:
By using hypothesis test at α = 0.01, we cannot conclude that the proportion of high school teachers who were single greater than the proportion of elementary teachers who were single
Step-by-step explanation:
let p1 be the proportion of elementary teachers who were single
let p2 be the proportion of high school teachers who were single
Then, the null and alternative hypotheses are:
: p2=p1
: p2>p1
We need to calculate the test statistic of the sample proportion for elementary teachers who were single.
It can be calculated as follows:
where
- p(s) is the sample proportion of high school teachers who were single ()
- p is the proportion of elementary teachers who were single ()
- N is the sample size (180)
Using the numbers, we get
≈ 1.88
Using z-table, corresponding P-Value is ≈0.03
Since 0.03>0.01 we fail to reject the null hypothesis. (The result is not significant at α = 0.01)