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ser-zykov [4K]
3 years ago
15

A new pair of sunglasses is regularly priced at $130.00. What

Mathematics
1 answer:
Vesna [10]3 years ago
6 0

Answer:

$ 84.50

Step-by-step explanation:

Regular price = $130

Discount = 35% of 130

               = \frac{35}{100}*130

              = 0.35 * 130

             = $ 45.50

Price of the sunglasses after discount = Regular price - discount

                                                               = 130 - 45.50

                                                              = $ 84.50

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Write an equation and solve:
Maksim231197 [3]
1. 47
2. 70.4 ft per min
3. 13.33333333333333
4 0
3 years ago
The Saxena family plans to install a light to illuminate part of their rectangular yard. Nikki and Dylan each proposed a differe
monitta

Options:

a. Nikki's proposed placement will light a greater area than Dylan's placement.

b.  Dylan's proposed placement will light a greater area than Nikki's placement.

c.  Both proposed placements will light the same sized area.

d. Nikki's proposed placement will light more than half the yard.

e. Dylan's proposed placement will light more than half the yard.

f.  Dylan's proposed placement will light exactly half of the yard.

g. Nikki's proposed placement will light less than half of the yard.

Answer:

C) Both proposed placements will light the same sized area.

F) Dylan's proposed placement will light exactly half of the yard.

Step-by-step explanation:

The area of a triangle is (base x height) / 2, and both lights illuminate the same base and height = (60 x 38) / 2 = 1,140 sq ft

Both Dylan's and Nikki's proposed placement will lit exactly half of the yard. The yard's total area = 60 x 38 = 2,280 sq ft, which is twice the area lit by the lights.

3 0
3 years ago
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cestrela7 [59]
Help we need help!!!
7 0
3 years ago
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I need help with this.
Sveta_85 [38]

Answer:

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6 0
2 years ago
A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021
egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

  • A is approximately <u>2020.022</u>

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

  • \displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

  • \displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}

Therefore, for the last term we have;

  • \displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

\displaystyle \frac{A}{2}  = \mathbf{ 1011 \cdot  \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460}  \right)}

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2} +\frac{1}{2} -  \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022}  \right)

Which gives;

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2022}  \right)

\displaystyle  A = 2 \times 1011 \cdot  \left(1 - \frac{1}{2022}  \right) = \frac{1032231}{511} \approx \mathbf{2020.022}

  • A ≈ <u>2020.022</u>

Learn more about the sum of a series here:

brainly.com/question/190295

8 0
2 years ago
Read 2 more answers
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