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rusak2 [61]
4 years ago
8

Craig can ride his bike at an average rate of 14 miles per hour in calm air. Traveling with the wind, he rode his bike 62 miles

in the same amount of time it took him to ride 50 miles against the wind. Find the speed of the wind.
Mathematics
1 answer:
Andreyy894 years ago
8 0

Answer: the speed of the wind is 1.5 mph

Step-by-step explanation:

Let x represent the speed of the wind.

Time = distance/speed

Craig can ride his bike at an average rate of 14 miles per hour in calm air. Traveling with the wind, his total speed would be (14 + x) mph

Time taken to travel 62 miles with the wind would be

62/(14 + x)

In the same amount of time it took him to ride 50 miles against the wind. His total speed would be

(14 - x) mph. Time taken to travel 50 miles is

50/(14 - x)

Since the time is the same, then

62/(14 + x) = 50/(14 - x)

Cross multiplying, it becomes

62(14 - x) = 50(14 + x)

868 - 62x = 700 + 50x

- 62x - 50x = 700 - 868

- 112x = - 168

x = - 168/-112

x = 1.5

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Sean has some candy bars that he wants to give away. He is going to give each person 1/18 of a bar, and he has 2 3/4 to give awa
julsineya [31]

Answer:

49 people

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Take the amount of candy and divide by the amount in a serving

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Plz hurry!!!! thank you!!!!
RoseWind [281]

Answer:

m\angle KLM=53.13^o

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the measure of angle KOM

In the triangle KOM

we have

KO=MO=r=5\ units

KM=8\ units

Applying the law of cosines

8^2=5^2+5^2-2(5)(5)cos(KOM)

64=50-50cos(KOM)

50cos(KOM)=50-64

50cos(KOM)=-14

cos(KOM)=-14/50

m\angle KOM=cos^{-1}(-14/50)

m\angle KOM=106.26^o

step 2

Find the measure of the arc KM

we know that

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we have

m\angle KOM=106.26^o

so

arc\ KM=106.26^o

step 3

Find the measure of angle KLM

we know that

The inscribed angle is half that of the arc comprising  

m\angle KLM=\frac{1}{2}[arc\ KM]

we have

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substitute

m\angle KLM=\frac{1}{2}[106.26^o]

m\angle KLM=53.13^o

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4 years ago
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