Answer: Hence, Probability that a coffee maker will have a defective cord is 0.376=37.6%.
Step-by-step explanation:
Since we have given that
Let A be the event of getting a faulty switch.
Let B be the event of getting a defective cord.
Here, P(A∪B) = 4% = 0.04
P(A∩B) = 0.1% = 0.001
P(A) = 2.5% = 0.025
We need to find P(B):
As we know that

Hence, Probability that a coffee maker will have a defective cord is 0.376=37.6%.
Answer:
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IF Factor x4−10x2+25
x4−10x2+25
=(x2−5)(x2−5)
Answer:
(x2−5)(x2−5)
IF simplify
x4−10x2+25
There are no like terms.
Answer:
=x4−10x2+25
Answer:
<u>see explanation</u>
Step-by-step explanation:
add 41; d = 60
Answer:
48
Step-by-step explanation:
Using Uclid's division algorithm, the HCF of 960 and 432 can be obtained as follows:
Here, 960 is greater and 432 is smaller. We divide 960 by 432.
STEP 1:
960 = 432*2 + 96
STEP 2:
Divide divisor (432) by remainder (96)
432 = 96 * 4 + 48
STEP 3:
Divide divisor (96) by remainder (48)
96 = 48 * 2 + 0
Since, remainder at this step is zero (0), so the HCF would be the divisor of this step which is 48.
Thus, HCF of 960 and 432 is 48