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Alex73 [517]
3 years ago
10

-r + 6 +8r -14 who do I do this

Mathematics
2 answers:
mixas84 [53]3 years ago
8 0

Combine like terms: add 8r and -r, and add 6 and -14.

8r-r +6-14

7r-8

BaLLatris [955]3 years ago
7 0

First you combine like terms

-r+8r = 7r

6-14 = -8

ANSWER = 7r-8

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HELP! the student council at woodlands middle school is planning a field trip. they polled randomly selected teachers and studen
gregori [183]

Answer:

c

Step-by-step explanation:

because on the chart is says 19% under burgers for teachers.

Tell me if it is right.

8 0
2 years ago
a slitter assembly contains 48 blades five blades are selected at random and evaluated each day for sharpness if any dull blade
son4ous [18]

Answer:

P(at least 1 dull blade)=0.7068

Step-by-step explanation:

I hope this helps.

This is what it's called dependent event probability, with the added condition that at least 1 out of 5 blades picked is dull, because from your selection of 5, you only need one defective to decide on replacing all.

So if you look at this from another perspective, you have only one event that makes it so you don't change the blades: that 5 out 5 blades picked are sharp. You also know that the probability of changing the blades plus the probability of not changing them is equal to 100%, because that involves all the events possible.

P(at least 1 dull blade out of 5)+Probability(no dull blades out of 5)=1

P(at least 1 dull blade)=1-P(no dull blades)

But the event of picking one blade is dependent of the previous picking, meaning there is no chance of picking the same blade twice.

So you have 38/48 on getting a sharp one on your first pick, then 37/47 (since you remove 1 sharp from the possibilities, and 1 from the whole lot), and so on.

Also since are consecutive events, you need to multiply the events.

The probability that the assembly is replaced the first day is:

P(at least 1 dull blade)=1-P(no dull blades)

P(at least 1 dull blade)=1-(\frac{38}{48}* \frac{37}{47} *\frac{36}{46}*\frac{35}{45}*\frac{34}{44})

P(at least 1 dull blade)=1-0.2931

P(at least 1 dull blade)=0.7068

5 0
3 years ago
Please help.
serious [3.7K]

The number of throws that the player make X follows binomial distribution.

The probability that the player makes x throws out of eleven throws is

P(X=x)=C(x,11)0.5^x(0.5)^{11-x}=C(x,11)0.5^{11}

The probability that the player makes at most nine out of eleven free throws

is

\sum_{x=0}^9C(x,11)0.5^{11}=1-\sum_{x=10}^{11}C(x,11)0.5^{11}\\ =1-C(10,11)0.5^{11}-C(11,11)0.5^{11}=1-\frac{12}{2^{11}} \\ =1-\frac{3}{512} =\frac{509}{512}

Correct choice is (B).

8 0
3 years ago
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aliya0001 [1]
Which part do you need help on?
7 0
2 years ago
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Choose the true statement about the graph of x-1 ≤ 2.​
frosja888 [35]

Answer:

circle on 1 and all numbers to the right shaded closed circle on 1 and all numbers to the left shaded

Step-by-step explanation:

4 0
3 years ago
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