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3 years ago

-r + 6 +8r -14 who do I do this

Mathematics

2 answers:

mixas84 [53]3 years ago

8 0

Combine like terms: add 8r and -r, and add 6 and -14.

8r-r +6-14

7r-8

BaLLatris [955]3 years ago

7 0

First you combine like terms

-r+8r = 7r

6-14 = -8

ANSWER = 7r-8

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What is the answer please help

Zinaida [17]

<h2>The answer is: D</h2>

(12 x 4= 48) + (4 x 2=8) = 56

The 4 is for the $4 amount spent on adult tickets. The 2 is for the $2 amount spent on child tickets.

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3 years ago

Read 2 more answers

List the elements of the set given below.

svetoff [14.1K]

Answer:

The set = {1, 2, 3, 4, 5}

Step-by-step explanation:

Let us explain how to solve this question

∵ The set = {x : x is a digit in the number 241,532)

→ That means the elements of the set are the digits of the given number

∴ The elements in this set are the digits of the number 241,532

∵ The digits of the number 241,532 are 2, 4, 1, 5, 3, 2

→ In any set of numbers,

Do not repeat any number
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∴ The elements of the set are 1, 2, 3, 4, 5

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3 years ago

4. A horizontal ellipse, centered at the origin has a major axis of 10 units and minor axis of 8 units. Write the

s2008m [1.1K]

Answer:

$\frac{x^2}{25} +\frac{y^2}{16} =1$

Step-by-step explanation:

For ellipses, the length of the major axis is represents as:

Major axis = $2a$

where $a$ is called the semi-major axis.

In this case since the major axis is equal to 10 units:

$10=2a$

solving for the semi-major axis $a$ :

$a=10/2\\a=5$

and also the minor axis of an ellipse is represented as:

Minor axis = $2b$

where $b$ is called the semi-minor axis.

Since the minor axis has a length of 8 units:

$8=2b$

solving for b:

$b=8/2\\b=4$

Now we can use the equation for an ellipse centered at the origin (0,0):

$\frac{x^2}{a^2} +\frac{y^2}{b^2} =1$

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$\frac{x^2}{5^2} +\frac{y^2}{4^2} =1$

and finall we simplify the expression to get the equation of the ellipse:

$\frac{x^2}{25} +\frac{y^2}{16} =1$

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3 years ago

What percent is equivalent to 7/20

expeople1 [14]

35%
divide whatever number you get move the decimal two spaces to the right and that is the percent.

4 0

3 years ago

You have two fair, six-sides dice. However, the dice have been modified so that instead or 1,2,3,4,5,6 the sides are numbered 1,

Tamiku [17]

Answer:

30.56%

Step-by-step explanation:

Let the sides on each dice be labeled as 1, 2a, 2b, 2c, 3, 4.

The sample space for the sum of the values being 4 is:

S={1,3; 3,1; 2a,2a; 2a,2b; 2a,2c; 2b,2a; 2b,2b; 2b,2c; 2c,2a; 2c,2b; 2c,2c}

There are 11 possible sums out of the 36 possible outcomes that result in a sum of 4. Therefore, the probability their total is 4 is:

$P(S) =\frac{11}{36}=0.3056 =30.56\%$

There is a 30.56% probability that their sum is 4.

6 0

3 years ago