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3 years ago

Solve the two-step equation. − 2 3 x – 21 4 = 27 4

Mathematics

2 answers:

svetoff [14.1K]3 years ago

7 0

Answer:

Step-by-step explanation:

I'm going to assume that the problem is -23x -214 = 274

And in that case...

1. First isolate the x-value by adding 214 to both sides of the equation:

-23x = 488

2. Then, divide both sides by -23 to truly get x alone:

x = $-\frac{488}{23}$ or -21.22

defon3 years ago

7 0

Answer:

x = -18

Add the opposite of the constant on the left:

-2/3x = 21/4 +27/4 = 48/4 = 12

Multiply the equation by the inverse of the coefficient of x:

x = (-3/2)(12) = -18

The solution is x = -18.

Step-by-step explanation:

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3 years ago

he amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and s

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Complete question:

He amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and standard deviation 1.4 minutes. Suppose that a random sample of n equals 47 customers is observed. Find the probability that the average time waiting in line for these customers is

a) less than 8 minutes

b) between 8 and 9 minutes

c) less than 7.5 minutes

Answer:

a) 0.0708

b) 0.9291

c) 0.0000

Step-by-step explanation:

Given:

n = 47

u = 8.3 mins

s.d = 1.4 mins

a) Less than 8 minutes:

$P(X$

P(X' < 8) = P(Z< - 1.47)

Using the normal distribution table:

NORMSDIST(-1.47)

= 0.0708

b) between 8 and 9 minutes:

P(8< X' <9) = $[\frac{8-8.3}{1.4/ \sqrt{47}}< \frac{X'-u}{s.d/ \sqrt{n}} < \frac{9-8.3}{1.4/ \sqrt{47}}]$

= P(-1.47 <Z< 6.366)

= P( Z< 6.366) - P(Z< -1.47)

Using normal distribution table,

$NORMSDIST(6.366)-NORMSDIST(-1.47)$

0.9999 - 0.0708

= 0.9291

c) Less than 7.5 minutes:

P(X'<7.5) = $P [Z< \frac{7.5-8.3}{1.4/ \sqrt{47}}]$

P(X' < 7.5) = P(Z< -3.92)

NORMSDIST (-3.92)

= 0.0000

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