Answer:
Let the speed of the train be x km/h.
Case 1:
Distance = 288 km
Speed = x km/h
Time = Distance/Speed
= 288/x h
Case 2:
Distance = 288 km
Speed = (x+4) km/h
Time = 288/x + 4 h
Since 288/x > 288/x + 4
288/x - 288/x+4 = 1
288[1/x - 1/x+4 ] = 1
[ x + 4 - x / x(x + 4) ] = 1/288
[4 / x^2 + 4x ] = 1/288
x^2 + 4x = 1152
x^2 + 4x - 1152 = 0
x^2 + 36x - 32x - 1152 = 0
x(x + 36) - 32(x + 36) = 0
(x + 36)(x - 32) = 0
x + 36 = 0 , x - 32 = 0
x = -36 , x = 32
x = -36 , rejected since speed cannot be negative.
Therefore , speed of the train = 32 km/h
The area of that square would be 121 cm^2 because :
area of square = length(width)
= 11(11)
= 121
Then you also have to square the units(cm). So the final answer would be 121 cm^2 (the " ^ "represents the exponentiation)
Answer:
The 11th term is 3072.
Step-by-step explanation:
First, find the common ratio and the first term. The common ratio is 6/3 or 2. The first term is 3.
Use the direct formula, xi=a*r^i-1, to find the eleventh term. a is first term, and i is the index or the number of the term.
Substitute: x11=3*2^(11-1)
Or x11=3*2^10
So x11 is 3072
Answer:
can i have the choices
Step-by-step explanation:
I believe it is -8 since the point where the line is x=80 and y=-10. Then you divide x/y (80/-10) and get -8.
