Answer:
32
Step-by-step explanation:
We need digits with only 0's and 1's.
There are 5 forms which we have to consider.
We have to consider 1-, 2-, 3-, 4-, 5-digit numbers.
1-digit number
For 1 digit number there is only 2 possibilities (0,1).
2-digit number
For 2 digit number the first digit will be fixed i-e 1 because if we take 0 to be the first digit it will reduce to one digit number, so first digit has to be 1. Now in the second digit place we have two possibilities 0 and 1.
So the total possible combination for 2-digit number is 1*2=2.
3-digit number
For 3 digit number first place is fixed with second and third having two possibilities giving us the combination for 3-digit number as 1*2*2=4.
4-digit number
Similarly for four digit number first place is fixed with the rest three with the possibility of two. So possible combination is 1*2*2*2=8.
5-digit number
For 5 digit we have the combination as 1*2*2*2*2=16.
So the total numbers left are 2+2+4+8+16=32.
