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quester [9]
3 years ago
13

Someone please help me

Mathematics
1 answer:
Stels [109]3 years ago
6 0

Answer:first one .

Step-by-step explanation:

n/a

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Is this right? Please help me
Lyrx [107]

Answer:

It is The answer is D

Step-by-step explanation:

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3 years ago
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Measure of angle A = 5 X, measure of angle B = 2X, measure of angle C = 110 degrees
Alex17521 [72]
5x+2x+110=180
7x=70
x=10
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A(a-bx)/x=2/3<br> PLEASE
RSB [31]

Answer:

This cannot be solved but it can be simplified

first we open the bracket

so we have

a²- abx/x = 2/3

next we cross multiply so it will be 3(a² - abx) = 2x

we get

3a² - 3abx = 2x

Next we factorise so we can get

3a(a-bx) =2x

I dont know what exactly you where asked but I hop this helps

7 0
3 years ago
Maddie's monthly take home pay is $3,500. She is making monthly payments of $250 for a student loan and $218 for a credit card.
iren2701 [21]

Answer:

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Step-by-step explanation:

4 0
3 years ago
In Vancouver, British Columbia, the probability of rain during a winter day is 0.42, for a spring day is 0.23, for a summer day
nadezda [96]

Answer:

31.82% probability that this day would be a winter day

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening

In this question:

Event A: Rain

Event B: Winter day

Probability of rain:

0.42 of 0.25(winter), 0.23 of 0.25(spring), 0.16 of 0.25(summer) or 0.51 of 0.25(fall).

So

P(A) = 0.42*0.25 + 0.23*0.25 + 0.16*0.25 + 0.51*0.25 = 0.33

Intersection:

Rain on a winter day, which is 0.42 of 0.25. So

P(A \cap B) = 0.42*0.25 = 0.105

If you were told that on a particular day it was raining in Vancouver, what would be the probability that this day would be a winter day?

P(B|A) = \frac{0.105}{0.33} = 0.3182

31.82% probability that this day would be a winter day

6 0
3 years ago
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