Answer:
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Step-by-step explanation:
Answer:
This problem requires us to calculate, the value of investment after 10 and 25 years, and also tell the time after which intial investment amount will double. Investment rate and initial investment amount is given in the question.
Value of investment after 10 year = 600(1+8%)^10 = $ 1,295
Value of investment after 25 year = 600(1+8%)^25 = $ 4,109
Time after which investment amount double (n)
1200 = 600 (1.08)^n
Log 2 = n log 1.08
n = 9 years
1.5x + 0.2y = 2.68....multiply by 0.3
1.6x + 0.3y = 2.98...multiply by - 0.2
------------------------
0.45x + 0.06y = 0.804 (result of multiplying by 0.3)
- 0.32x - 0.06y = - 0.596 (result of multiplying by - 0.2)
----------------------add
0.13x = 0.208
x = 0.208/0.13
x = 1.6
1.5x + 0.2y = 2.68
1.5(1.6) + 0.2y = 2.68
2.4 + 0.2y = 2.68
0.2y = 2.68 - 2.4
0.2y = 0.28
y = 0.28/0.2
y = 1.4
solution (they intersect at) (1.6,1.4)
Answer:
Third option
Step-by-step explanation:
We can't factor this so we need to use the quadratic formula which states that when ax² + bx + c = 0, x = (-b ± √(b² - 4ac)) / 2a. However, we notice that b (which is 6) is even, so we can use the special quadratic formula which states that when ax² + bx + c = 0 and b is even, x = (-b' ± √(b'² - ac)) / a where b' = b / 2. In this case, a = 1, b' = 3 and c = 7 so:
x = (-3 ± √(3² - 1 * 7)) / 1 = -3 ± √2
Answer:
The expected value of playing the game is $0.75.
Step-by-step explanation:
The expected value of a random variable is the weighted average of the random variable.
The formula to compute the expected value of a random variable <em>X</em> is:
The random variable <em>X</em> in this case can be defined as the amount won in playing the game.
The probability distribution of <em>X</em> is as follows:
Number on spinner: 1 2 3 4 5 6
Amount earned (<em>X</em>): $1 $4 $7 $10 -$8.75 -$8.75
Probability: 1/6 1/6 1/6 1/6 1/6 1/6
Compute the expected value of <em>X</em> as follows:
Thus, the expected value of playing the game is $0.75.
