Answer:
tan53=x/14
Step-by-step explanation:
solve after that with inverse tan and simple algebra
10 pieces of silverware laid in a row if 3 are identical spoons, 4 are identical forks, and 3 are identical knifes
The arrangement of 'm' objects on which 'n' objects are of same kind is 
Given: 10 pieces of silverware so its 10!
3 are identical spoons so its 3!
4 are identical forks so its 4!
and 3 are identical knifes so its 3!
Arrangements made =
= 4200
Answer:
Step-by-step explanation:
Vertical Asymptote: x=2Horizontal Asymptote: NoneEquation of the Slant/Oblique Asymptote: y=x 3+23 Explanation:Given:y=f(x)=x2−93x−6Step.1:To find the Vertical Asymptote:a. Factor where possibleb. Cancel common factors, if anyc. Set Denominator = 0We will start following the steps:Consider:y=f(x)=x2−93x−6We will factor where possible:y=f(x)=(x+3)(x−3)3x−6If there are any common factors in the numerator and the denominator, we can cancel them.But, we do not have any.Hence, we will move on.Next, we set the denominator to zero.(3x−6)=0Add 6 to both sides.(3x−6+6)=0+6(3x−6+6)=0+6⇒3x=6⇒x=63=2Hence, our Vertical Asymptote is at x=2Refer to the graph below:enter image source hereStep.2:To find the Horizontal Asymptote:Consider:y=f(x)=x2−93x−6Since the highest degree of the numerator is greater than the highest degree of the denominator,Horizontal Asymptote DOES NOT EXISTStep.3:To find the Slant/Oblique Asymptote:Consider:y=f(x)=x2−93x−6Since, the highest degree of the numerator is one more than the highest degree of the denominator, we do have a Slant/Oblique AsymptoteWe will now perform the Polynomial Long Division usingy=f(x)=x2−93x−6enter image source hereHence, the Result of our Long Polynomial Division isx3+23+(−53x−6)
Answer:
The system of equations that models the problem is:

Step-by-step explanation:
A system of equations is a set of two or more equations with several unknowns in which we want to find a common solution. So, a system of linear equations is a set of (linear) equations that have more than one unknown that appear in several of the equations. The equations relate these variables or unknowns to each other.
In this case, the unknown variables are:
- H: price of a can of corn beef hash
- C: price of a can of creamed chipped beef
Knowing the unit price of a product, the price of a certain quantity of that product is calculated by multiplying that quantity by the unit price. So the price for 2 cans of ground beef hash can be calculated as 2 * H and the price for 3 cans of ground beef with cream can be calculated as 3 * C. Jan paid $ 4.95 for those amounts from both cans. This means that the sum of the can prices must be $ 4.95. So: <u><em>2*H + 3*C= 4.95 Equation (A)</em></u>
Thinking similarly, if Wayne bought 3 cans of corn beef hash and 2 cans of creamed chipped beef for $5.45, Wayne's buy can be expressed by the equation:
<u><em>3*H + 2*C= 5.45 Equation (B)</em></u>
Finally, <u><em>the system of equations that models the problem is:</em></u>
<u><em></em></u>
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Key words of this equation are of which means multiply. This means that essetnially it is expressing 4/1 multiplied by 5/12 which is 20/12 which is 1.7 (rounded)