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-Dominant- [34]
2 years ago
11

Solve the inequality 15 ≥ q + 3

Mathematics
1 answer:
oksano4ka [1.4K]2 years ago
5 0

Answer:

q\le \:12

Step-by-step explanation:

<u>Solving</u>

\mathrm{Switch\:sides}  (Not a required step)

q+3\le \:15

\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}

q+3-3\le \:15-3\\=q\le \:12

\bold{q\le \:12}

<u>Graphing</u>

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What are the coordinates of the point that is common to the graph of f(x) = (2/3) ^ x and the graph of f(x) = (3/2) ^ x
kiruha [24]

Answer:

Both point are y=0. The difference between the two is that 2/3 is always decressing and 3/2 is always incressing.

Step-by-step explanation:

7 0
2 years ago
ANSWER THE QUESTIONS PLEASE IT IS ON BEARING
artcher [175]

9514 1404 393

Answer:

  (i) x° = 70°, y° = 20°

  (ii) ∠BAC ≈ 50.2°

  (iii) 120

  (iv) 300

Step-by-step explanation:

(i) Angle x° is congruent with the one marked 70°, as they are "alternate interior angles" with respect to the parallel north-south lines and transversal AB.

  x = 70

The angle marked y° is the supplement to the one marked 160°.

  y = 20

__

(ii) The triangle interior angle at B is x° +y° = 70° +20° = 90°, so triangle ABC is a right triangle. With respect to angle BAC, side BA is adjacent, and side BC is opposite. Then ...

  tan(∠BAC) = BC/BA = 120/100 = 1.2

  ∠BAC = arctan(1.2) ≈ 50.2°

__

(iii) The bearing of C from A is the sum of the bearing of B from A and angle BAC.

  bearing of C = 70° +50.2° = 120.2°

The three-digit bearing of C from A is 120.

__

(iv) The bearing of A from C is 180 added to the bearing of C from A:

  120 +180 = 300

The three-digit bearing of A from C is 300.

8 0
2 years ago
What is (3⁴×5⁴)-³ =?​
Kay [80]

Answer:

The solution to the given expression is 1/2562890625

Step-by-step explanation:

(3⁴ × 5⁴)⁻²

Simplify the terms inside the parentheses. 3⁴ × 5⁴ is the same as 15⁴ because even though the base numbers are different, the exponents are the same which makes it similar.

(15⁴)⁻²

Now, for this step, we are going to add the exponents because when multiplying, the exponential numbers add together. So 4 × -2 = -8.

15⁻⁸

Since we can not have a negative exponent, we are going to change this into a fraction. We do this by putting this term in a fraction where 1 is the numerator and the term is the denominator.

1 / 15⁻⁸

Now, we simplify the term on the bottom.

1 / 2562890625

So, this is the solution to the problem.

7 0
3 years ago
Tickets to a sporting event cost $125 each. What's a reasonable domain and range.
djverab [1.8K]

The domain and the range of a function is the set of input and output values of the function.

The domain is the set of all whole numbers.

The range is the set of all whole numbers.

Let the number of tickets be x, and the revenue be y.

So, the revenue function will be:

y = 125

The number of tickets cannot be less than 0.

So, the domain of the revenue function is

domain=0,∞

The above means that, the domain is the set of all whole numbers

Similarly, the revenue cannot be less than 0.

So, the range of the revenue function is

range = 0,∞

The above means that, the range is also the set of all whole numbers (in multiples of 125).

to know more about range and domain;

visit;brainly.com/question/28135761

#SPJ9

3 0
1 year ago
Can someone please help me I really need help please help me
scZoUnD [109]

Answer:

18.87 square cm.

Step-by-step explanation:

The area of the rectangle will be (4 + 4) * 4, since the length of the rectangle would be the diameter of the circle, and the width of the rectangle would be the radius. (4 + 4) * 4 = 8 * 4 = 32 square cm.

Then, we can calculate the area of the semicircle. The area of a circle is pi * r^2, so the area of a semicircle will be half of that. pi * (4^2) / 2 = pi * 16 / 2 = 8pi. 8 * 3.14159265 = 25.1327412 square cm.

The shaded area of the middle of the shape will then be 32 - 25.1327412 = 6.8672588 square cm.

The two triangles will have the same area. Their bases will be 14 minus the diameter of the circle, then divide that by 2 to get each separate base. 14 - 8 = 6 / 2 = 3. The heights of the triangles will be the radius of the circle, or 4 cm.

1/2 * 3 * 4 = 1/2 * 12 = 12/2 = 6. That is the area of one triangle, so the area of both triangles would be 6 * 2 = 12 square cm.

6.8672588 + 12 = 18.8672588, or 18.87 square cm.

Hope this helps!

3 0
2 years ago
Read 2 more answers
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