Answer:n+5=2n+12, n=-7
Step-by-step explanation:
I am assuming that 114114 is actually 114.
Toni: 20 + 0.80/lap
Marcy: 15 + 0.85/lap
Marcy: x laps
Toni: 114x laps
[20 + 0.80(114x)] + [15 + 0.85x] = 257
20 + 91.2x + 15 + 0.85x = 257
92.05x = 257 - 35
92.05x = 222
x = 222/92.05
x = 2.41 laps
Marcy: x = 2.41 laps
Toni: 114x = 114(2.41) = 274.74 laps
20 + 0.80(274.74) = 20 + 219.79 = 239.79 or 240
15 + 0.85(2.41) = 15 + 2.05 = 17.05 or 17
240 + 17 = 257
I think I can.
Let's do it together:
Let's call the number of buses 'B', and the number of vans 'V'.
(Pretty clever so far, don't you think ?)
OK. What do we know ?
-- Each bus holds 51 passengers. The number of passengers in 'B' buses is 51B.
-- A van holds 10 passengers. The number of passengers in 'V' vans is 10V.
-- The total number of passengers ... (51B + 10V) ... is 142.
-- The total number of vehicles ... (B + V) ... is 6, because there are 6 drivers.
Can you make a system of equations out of that information yet ?
How about this:
51B + 10V = 142
B + V = 6
I really think you can handle it from here.
=======================================
Multiply the 2nd equation by 10 :
51B + 10V = 142
10B + 10V = 60
Subtract the 2nd equation from the 1st one:
41B = 82
Divide each side by 41: <em> B = 2 buses</em>
2 buses . . . . 2 drivers . . . . 2 x 51 = 102 passengers
4 vans . . . . . 4 drivers . . . . . 4 x 10 = 40 passengers
6 vehicles . . . 6 drivers . . . . . 102 + 40 = 142 passengers
Answer:
114688
Step-by-step explanation:
i think this is the answer