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Gwar [14]
3 years ago
12

In ABC, b = 68 inches, B=65° and C=93º. Find the length of a, to the nearest inches

Mathematics
1 answer:
sp2606 [1]3 years ago
3 0

Answer:

28inches

Step-by-step explanation:

∠A + ∠B + ∠C = 180°

∠A + 65° +93° = 180°

∠A + 158° = 180°

∠A= 180°-158° = 22°

Using Law of Sines

a/sinA= b/sinB

a/sin22= 68 inches/sin65

a/sin22 = 68/0.9063 = 75.03

a = 75.03 x sin 22

a = 75.03 x 0.3746 = 28.106238≈28 inches

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