The Laplace of the given equation is
.
According to the statement
we have given that the equation and we have to solve this problem with the help of the Laplace transform.
So, According to the statement
the given equation is
y'' − 4y' + 4y = t^3e^2t, y(0) = 0, y'(0) = 0
And the Laplace transform is an integral transform method which is particularly useful in solving linear ordinary differential equations.
Firstly fill the value of the Laplace of the second order derivative and put x = 0 in the equation
And same it with the first order of the derivative.
And then the Laplace of the equation become

So, The Laplace of the given equation is 
Learn more about Laplace transform here
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Let’s simplify!
y = 6(x - 2)² - 3
y = 6(x - 2)(x - 2) - 3
y = 6(x² - 2x - 2x + 4) - 3
y = 6(x² - 4x + 4) - 3
y = 6x² - 24x + 24 - 3
y = 6x² - 24x + 21
Answer:
There would be 5, 4 point questions and 10, 3 point answers
Step-by-step explanation:
Answer:
h=2πr
Step-by-step explanation:
h=s-2πr^2;h=s-r^2;h=s-r:2πr
C. -14x
Just multiply 3 with -5 and get -14x. And then add a positive x to get -14x