4 years ago

What is the slope of a line perpendicular to the line whose equation is 3x-12y=2163x−12y=216.

Mathematics

2 answers:

zubka84 [21]4 years ago

8 0

Answer:

Slope (m) = 3

Step-by-step explanation:

Here 3x-12y-216=0

Reducing into slope intercept form

-12y= -3x + 216

12y = 3x - 216

Which is in the form of, y = mx + c

Slope (m) = 3

Keith_Richards [23]4 years ago

5 0

Answer:

Deleted account

Step-by-step explanation:

Here 3x-12y-216=0

Reducing into slope intercept form

-12y= -3x + 216

12y = 3x - 216

Which is in the form of, y = mx + c

Slope (m) = 3

Step-by-step explanation:

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