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givi [52]
2 years ago
13

Karen has 3 1/4 feet of ribbon .She uses 1 3/4 feet to wrap gifts .Which shaded part of the model shows 1 3/4

Mathematics
1 answer:
andriy [413]2 years ago
4 0

Answer:

3 1/4 - 1 3/4  = 1 1/2

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Find the derivate of : y = ln(x)/5x <br> y'=
DerKrebs [107]
The answer should be around

y’=1/5 + 1/5 x In(x)
4 0
3 years ago
How do I do this problem?
goldenfox [79]

so a quadrilateral is a figure with 4 sides. So looking at the picture I see 5 rhombi and 7 squares. So all together thats 12 quadrilaterals  

So to find the ration you have to do:

amount of thing: whole

so in this case it would be

12:24

which you can simplify

normally you'd simplify to 1:2 but that doesn't seem like an option so I'd go with the one closest to that ratio


4 0
3 years ago
Read 2 more answers
a basketball player looks directly at the rim that is 10 feet high. the angle of elevation from her eye level, which is 6feet ab
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Her horizontal distance to the rim satisfies the ratio
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6 0
3 years ago
Directed line segment AB has endpoints A(2,3) and B(8,15). Point P has coordinated P(6,11). What ratio does P partition AB into?
Vladimir79 [104]
Refer to the graph shown below. It confirms that points A, B and P are
 collinear.

Calculate the length of AP (as a).
a = √[(6 - 2)² + (11 - 3)²]
   = 8.9443

Calculate the length of BP (as b).
b = √[(8 - 6)² + (15 - 11)²]
   = 4.4721

Calculate ratio a/b.
a/b = 8.9443/4.4721 = 2
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7 0
3 years ago
The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.917 g and a standard deviation
Nutka1998 [239]

Answer:

z = \frac{0.872-0.917}{\frac{0.303}{\sqrt{37}}}= -0.903

And we can find this probability to find the answer:

P(z

And using the normal standar table or excel we got:

P(z

Step-by-step explanation:

Let X the random variable that represent the amounts of nocatine of a population, and for this case we know the distribution for X is given by:

X \sim N(0.917,0.303)  

Where \mu=0.917 and \sigma=0.303

We have the following info from a sample of n =37:

\bar X= 0.872 the sample mean

And we want to find the following probability:

P(\bar X \leq 0.872)

And we can use the z score formula given by;

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for the value of 0.872 we got:

z = \frac{0.872-0.917}{\frac{0.303}{\sqrt{37}}}= -0.903

And we can find this probability to find the answer:

P(z

And using the normal standar table or excel we got:

P(z

6 0
3 years ago
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