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DIA [1.3K]
3 years ago
9

How do you know when to put an open or closed circle when graphing inequalities?

Mathematics
1 answer:
Marina CMI [18]3 years ago
3 0
An open circle means not equal to. So, if your equation is x < 4, You would put an OPEN circle at four because it can't equal four.
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The circle below is centered at the point (4,3) and has a radius length 5. What is its equation
Crazy boy [7]
The equation of a circle centred at point (m,n) and radius r is given by

<span>(x-m)² + (y-n)² = r²
</span>-------------------------------------------------------------
Centre = (4,3)
radius = 5

Equation:
(x - 4)² + (y - 3)² = 5²
⇒ x² - 8x + 16 + y² - 6y + 9 = 25
⇒ x² + y² - 8x - 6y + 25 = 25
⇒ x² + y² - 8x - 6y = 0

The equation of the circle is x² + y² - 8x - 6y = 0

Hope it helps!
3 0
3 years ago
Read 2 more answers
What is the factored form of _________?
enyata [817]

Answer:

C

Step-by-step explanation:

The expression given is a difference of cubes and factors as

a³ - b³ = (a - b)(a² + ab + b²)

8x^{24} = (2x^{8})³ ⇒ a = 2x^{8}

27y^{6} = (3y²)³ ⇒ b = 3y²

Hence 2 factors are

(2x^{8} - 3y²) and

((2x^{8})² + (2x^{8} × 3y²) + (3y²)²)

= (4x^{16} + 6x^{8}y² + 9y^{4})

Hence the factored form of the expression is C

4 0
3 years ago
How would I solve number six?
Basile [38]

Answer:

Angle ABC is equal to 130.4°

Step-by-step explanation:

When an angle is bisected, it is divided into two equal parts, so if BD bisects ∠ABC, then the two angles that add up to it, ∠ABD and  ∠DBC, must be equivalent.

We know that ∠ABD equals 65.2, so that must mean that ∠DBC also equals 65.2.

Here is our equation:

∠ABC=∠ABD+∠DBC

After substituting, we will get

∠ABC=65.2+65.2=130.4

130.4° is the measure of ∠ABC.

6 0
3 years ago
Read 2 more answers
Water has a freezing point of 32 degrees. Murcury has a freezing point that is 70 degrees lower. What is the freezing point of m
Mekhanik [1.2K]

Answer:

-38 degrees

Step-by-step explanation:

32-70

= -38

8 0
3 years ago
Find the linear approximation of f(x)=lnx at x=1 and use it to estimate ln(1.38).
RideAnS [48]
\bf f(x)=y=ln(x)\qquad &#10;\begin{cases}&#10;x=1\\&#10;y=ln(1)\to y=0&#10;\end{cases}\\\\&#10;-----------------------------\\\\&#10;\left. \cfrac{dy}{dx}=\cfrac{1}{x} \right|_{x=1}\implies 1\impliedby m&#10;\\\\\\&#10;\textit{now, we know that }&#10;\begin{cases}&#10;x=1\\&#10;y=0\\&#10;m=1&#10;\end{cases}\implies y-0=1(x-1)\implies y=x-1

now, you're asked to use it when ln(1.38), which is just another way of saying x = 1.38

so set x = 1.38 and see what "y" is
5 0
3 years ago
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