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4 years ago

Solve 5(a – 7) 11 = 2a – 3(a 4)

Mathematics

1 answer:

oksano4ka [1.4K]4 years ago

7 0

The answer is a= 77/13

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One more than the product of 15 and g

givi [52]

(15 x g) + 1

is your answer

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4 years ago

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Find the length of the third side. If necessary, write in simplest radical form. 9 5

tigry1 [53]

Step-by-step explanation:

$(9) {}^{2} = (5) {}^{2} + (x) {}^{2} \\ 81 = 25 + {x}^{2} \\ {x}^{2} = 56 \\ x = 2 \sqrt{14} = 7.4$

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3 years ago

Please help me solve this

Snowcat [4.5K]

Answer:

its 12

Step-by-step explanation:

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3 years ago

Prove (correctly) that if 1 = -1, then 2=1

Nitella [24]

Answer:

This may not be entirely satisfied proof but you should get the idea.

Proof: Start with 1 = -1.

Then we know that if a= b then a + c = b + c and also a / c = b / c.

So we can add 1 to both sides.

We have 1 + 1 = -1 + 1 ⇒ 2 = 0.

Now divide both sides by 2 and we would have 1 = 0.

Now add both sides by 1. This yields 2 = 1.

Therefore if 1 = -1 then 2 = 1.

QED

6 0

3 years ago

1000.0 cm3 of a metallic cylinder has a mass of 556 gram. Calculate the density of the cylinder.

natima [27]

Answer:

$\text{Density}=\frac{0.556\text{ Grams}}{\text{ cm}^3}$

Step-by-step explanation:

We are asked to find the density of a cylinder whose volume is 1000.0 cubic cm and mass is 556 grams.

$\text{Density}=\frac{\text{Mass}}{\text{Volume}}$

Substitute the given values:

$\text{Density}=\frac{556\text{ Grams}}{1000.0\text{ cm}^3}$

$\text{Density}=\frac{0.556\text{ Grams}}{\text{ cm}^3}$

Therefore, the density of the metallic cylinder is 0.556 grams per cubic centimeter.

6 0

3 years ago