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2 years ago

I need help.................

Mathematics

1 answer:

Yanka [14]2 years ago

8 0

Answer:

-33 and -21

Step-by-step explanation:

-36, <u>-33</u>, -30, -27, -24, <u>-21</u>, -18

-36

-36 + 3 = -33

-33 + 3 = -30

-30 + 3 = -27

-27 + 3 = -24

-24 + 3 = -21

-21 + 3 = -18

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(x+16)²=12 plz help me and show work

Readme [11.4K]

Answer:

The answer is $x=-16$ ± $2\sqrt{3}$ in exact form or $x=-12.535898$ , $x=-19.464102$ in decimal form.

Step-by-step explanation:

To solve this problem, start by moving all terms to the left side of the equation and simplify. Simplify the equation by subtracting 12 from both sides of the equation and squaring $x+16$ , which will look like $x^{2} +32x+256-12=0$ . Next, simplify the equation again, which will look like $x^{2} +32x+244=0$ .

Then, use the quadratic formula to find the solutions. The quadratic formula looks like $\frac{-b(+-)\sqrt{b^{2}-4ac } }{2a}$ .

For this problem, the quadratic variables are as follows:

$a=1$

$b=32$

$c=244$

The next step is to substitute the values $a=1$ , $b=32$ , and $c=244$ into the quadratic formula and solve. The quadratic formula will look like $\frac{-32(+-)\sqrt{32^2-4(1*244)} }{2*1}$ . To simplify the equation, start by simplifying the numerator, which will look like $x=\frac{-32(+-)4\sqrt{3} }{2*1}$ . Then, multiply 2 by 1 and simplify the equation, which will look like $x=-16(+-)2\sqrt{3}$ . The final answer is $x=-16$ ± $2\sqrt{3}$ in exact form. In decimal form, the final answer is $x=-12.535898$ , $x=-19.464102$ .

6 0

2 years ago

35/20 in simplest form

Andrew [12]

Answer:

7/4

Step-by-step explanation:

35 divided by 5

20 divided by 5

3 0

3 years ago

Read 2 more answers

Consider the rational expression (IMAGE ATTACHED)

Keith_Richards [23]

Answer:

3x² is a term in the numerator
x + 1 is a common factor
The denominator has 3 terms

Step-by-step explanation:

You can identify terms and count them before you start factoring. Doing so will identify 3x² as a term in the numerator, and will show you there are 3 terms in the denominator.

When you factor the expression, you get ...

$\dfrac{3x^2-3}{3x^2+2x-1}=\dfrac{3(x^2-1)}{(3x-1)(x+1)}=\dfrac{3(x-1)(x+1)}{(3x-1)(x+1)}$

This reveals a common factor of x+1.

So, the above three observations are true of this rational expression.

3 0

3 years ago

Ok I need help ASAP pls like right now points are going giving and mark brainless pls help I need answers for 1,2,3

Schach [20]

Answer:

1. 30 student

2. 120 student's didn't vote

3. 7 quarters

Step-by-step explanation:

1. first, see how many games can be played:

45÷3 = 15

then, multiply the number of games by two because 2 students can play per game

15 • 2 = 30

2. first, figure out what percent of students did not vote:

100 - 60 = 40%

then, multiply the number of students total (300) by the decimal of the percent that did not vote to find the number of students who didn't vote:

300 • .40 = 120 student's didn't vote

3. first, find how much 9 dimes is:

1 dime = $0.10

9 dimes = 9 • $0.10 = $0.90

then, find how much money kerry had:

$2.65 - $0.90 = $1.75

finally, find out how many quarters kerry had by dividing the amount of money she had by the worth of a quarter:

1 quarter = $0.25

$1.75 ÷ $0.25 = 7 quarters

8 0

3 years ago

The table gives estimates of the world population, in millions, from 1750 to 2000. year population year population 1750 790 1900

Tems11 [23]

The poopulation exponential model is given by

$P(t)=P_0e^{kt}$

Where, P(t) is the population after year t; Po is the initial population, t is the number of years from the starting year; k is the groth constant.

Given that the population in 1750 is 790 and the population in 1800 is 970, we obtain the population exponential equation as follows:

$970=790e^{50k} \\ \\ \Rightarrow e^{50k}=1.228 \\ \\ \Rightarrow 50k=\ln{1.228}=0.2053 \\ \\ \Rightarrow k=0.0041$

Thus, the exponential equation using the 1750 and the 1800 population values is $P(t)=790e^{0.0041t}$

The population of 1900 using the 1750 and the 1800 population values is given by

$P(t)=790e^{0.041\times150} \\ \\ =790e^{0.6158}=790(1.8511) \\ \\ =1,462$

The population of 1950 using the 1750 and the 1800 population values is given by

$P(t)=790e^{0.041\times200} \\ \\ =790e^{0.821}=790(2.2729) \\ \\ =1,796$

From the table, it can be seen that the actual figure is greater than the exponential model values.

7 0

3 years ago