Question

HELLPPP Solve the system by substitution. -9x-10y=12 −3x+3=y

Answer 1

HELLPPP

Solve the system by substitution.
-9x-10y=12
−3x+3=y


X=2
Y= -3

Answer 2

Answer:

$x=2\\y=-3$

Step-by-step explanation:

We have:

$-9x-10y=12\\-3x+3=y$

Since we already have a variable value ($y$) in the second equation, it would be easiest to substitute the value for $y$ in the first equation:

$-9x-10(-3x+3)=12$

Distribute $-10$ into $(-3x+3)$:

$-9x+30x-30=12$

Combine like terms:

$21x-30=12$

Add $30$ to both sides of the equation:

$21x=42$

Divide by the coefficient of $x$, which is $21$:

$x=2$

_

Now that we have our $x$ value, we can substitute that in to the second equation to find our $y$ value:

$-3(2)+3=y$

Multiply:

$-6+3=y$

Combine like terms:

$-3=y$