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sertanlavr [38]
3 years ago
12

The wall of a room are representations of what basic element of geometry

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
3 0
The wall of a room are representations of what basic element of geometry is “plane”
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(−2/3)x(1/6) please answer
Monica [59]

Answer:

The answer would be -1/9. The decimal form would be -0. 111111. Hope this helped, and if it did, please like the answer and rate it. ty! :)

5 0
3 years ago
Read 2 more answers
Brainliest goes to whoever answers correctly and explains also if you want extra points answer my other questions
Liula [17]

Answer:

Step-by-step explanation:

Question 1 = 2002

2002 - 2000 = 2 (the years since 2000)

y = (275 x 2) + 50

y = 875

Question 2 = 1425 likes

2005 - 2000 = 5 (the years since 2000)

y = (275 x 5) + 50

y = 1425

Question 3 = 2018

Since y = 5000

5000 - 50(the extra likes) = 4950

4950 / 275 = 18 (the years since 2000)

2000 + 18 = 2018 (the year)

8 0
3 years ago
At a large university, the mean amount spent by students for cell phone service is $58.90 per month with a standard deviation of
zhenek [66]

Answer:

2.28% probability that the mean amount of their monthly cell phone bills is more than $60

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 58.90, \sigma = 3.64, n = 44, s = \frac{3.64}{\sqrt{44}} = 0.54875

What is the probability that the mean amount of their monthly cell phone bills is more than $60?

This is 1 subtracted by the pvalue of Z when X = 60. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{60 - 58.90}{0.54875}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

2.28% probability that the mean amount of their monthly cell phone bills is more than $60

4 0
3 years ago
Volume of a triangular pyramid with a slant height of 8 and base of 6 wide 6 across or 8 by 6 by 6
mario62 [17]
288 is the volume. I think.

8 0
3 years ago
Will mark as Brainliest.
Brilliant_brown [7]
2a^4+5a^3-13a^2+19a-28
7 0
3 years ago
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