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ArbitrLikvidat [17]
3 years ago
7

Sandra bought a tube of toothpaste for $1.89, shampoo for $3.19 and a jar of peanuts for $2.29 from the local supermarket. Using

rounding to the nearest whole number, estimate the total cost of her purchases.
Mathematics
2 answers:
Wittaler [7]3 years ago
8 0

Answer:

The total cost of her purchases to the nearest whole number is $7.

Step-by-step explanation:

Consider the provided information.

Sandra bought a tube of toothpaste for $1.89, shampoo for $3.19 and a jar of peanuts for $2.29 from the local supermarket.

Now find how much she spent.

Add the numbers 1.89, 3.19 and 2.29

1.89+3.19+2.29=7.37

So, Sandra the total cost of her purchases is $7.37

we need to rounding to the nearest whole number.

Consider the number 7.37

Here 3 is at tenths place which is less than 5. So don't need to change ones place digit.

So the round off to the nearest whole number is 7.

The total cost of her purchases to the nearest whole number is $7.

uranmaximum [27]3 years ago
5 0
To find the total cost, you need to add these numbers together

1.89 + 3.19 + 2.29 = 7.37
you get 7.37 as your answer, but you need to round this to the nearest whole number.

rounding 7.37 will make it 7.

the total cost is about $7
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3 years ago
When the effective interest rate is 9% per annum, what is the present value of a series of 50 annual payments that start at $100
ser-zykov [4K]

Answer:

$1,109.62

Step-by-step explanation:

Let's first compute the <em>future value FV.</em>  

In order to see the rule of formation, let's see the value (in $) for the first few years

<u>End of year 0</u>

1,000

<u>End of year 1(capital + interest + new deposit)</u>

1,000*(1.09)+10  

<u>End of year 2 (capital + interest + new deposit)</u>

(1,000*(1.09)+10)*1.09 +10 =

\bf 1,000*(1.09)^2+10(1+1.09)

<u>End of year 3 (capital + interest + new deposit)</u>

\bf (1,000*(1.09)^2+10(1+1.09))(1.09)+10=\\1,000*(1.09)^3+10(1+1.09+1.09^2)

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\bf FV=1,000*(1.09)^{50}+10(1+1.09+(1.09)^2+...+(1.09)^{49}

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\bf 1+1.09+(1.09)^2+...+(1.09)^{49}

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\bf \frac{(1.09)^{50}-1}{1.09-1}=815.08356

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\bf FV=1,000*(1.09)^{50}+10*815.08356=82,508.35564

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\bf PV=\frac{FV}{(1.09)^{50}}=\frac{82508.35564}{74.35572}=1,109.616829\approx \$1,109.62

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2 years ago
Suppose that documentation lists the average sales price of a single-family home in the metropolitan Dallas/Ft. Worth/Irving, Te
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Answer:

"0.0373" seems to be the appropriate solution.

Step-by-step explanation:

The given values are:

n₁ = 43

n₂ = 35

\bar{x_1}=217800

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Now,

The test statistic will be:

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On substituting the given values in the above formula, we get

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then,

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