<u>M</u><u>e</u><u>t</u><u>h</u><u>o</u><u>d</u><u> </u><u>1</u><u> </u><u>:</u>
replace x and y by their value 1 and 3
3 = 4(1) - 1 = 4-1 = 3
2(1) + 3 = 2 + 3 = 5
correct
<u>M</u><u>e</u><u>t</u><u>h</u><u>o</u><u>d</u><u> </u><u>2</u><u> </u><u>:</u>
y = 4x - 1
2x + y = 5
y = 4x - 1
y = -2x + 5
y - y = 4x - 1 - ( -2x + 5 )
0 = 4x - 1 + 2x - 5
6x - 6 = 0
6x = 6
x = 6/6 = 1
y = 4x - 1
y = 4(1) - 1
y = 3
correct
Answer:
Therefore there are 35 number of 2-point questions and 15 number of 5-point questions.
Step-by-step explanation:
i) let the number of 2 point question is x.
ii) let the number of 5 point questions be y
iii) total number of questions is 50
iv) therefore x + y = 50
v) it is also given that 2x + 5y = 145
vi) solving for the two equations found in iv) and v). Multiplying iv) by 2 we get
2x + 2y = 100
vii) subtracting equation vi) from equation v) we get 3y = 45.
viii) Therefore y = 15.
ix) using the value in viii) and substituting in iv) we get x + 15 = 50.
Therefore x = 50 - 15 = 35
x) Therefore there are 35 number of 2-point questions and 15 number of 5-point questions.
A is located, as you look A is past -2 almost hitting -3 making the mark 2.8 so the answer is A
Answer:
[C] 25π square inches
Step-by-step explanation:
<u><em>Given that:</em></u>
<em>the long hand of the clock is about 5 inches long.</em>
<u><em>To Find:</em></u>
<em>What is the approximate area of the clock face?</em>
<u><em>Solve:</em></u>
<em>Formula - </em><em>A =πr²</em>
<em>Note that;</em>
<em>π = 3.14 (about)</em>
<em>Radius - 5 inches</em>
<em>A =πr²</em>
<em>A = 3.14(5)²</em>
<em>A = 3.14(25)</em>
<em>A = 78.5</em>
<em>Now let see the answer choices:</em>
<em>A. 5π square inches ≈ 5(3.14) = 15.7</em>
<em>B. 10 π square inches ≈ 10(3.14) = 31.4</em>
<em>C. 25 π square inches ≈ 25(3.14) = 78.5</em>
<em>D. 100 π square inches ≈ 100(3.14) = 314</em>
<em />
<em>Hence, the answer is [C] 25 π square inches </em>
<em />
<u><em>Kavinsky~</em></u>
