Answer:
A, D , and E
Step-by-step explanation:
We have that:
![\overline{CD} = 12 \: units](https://tex.z-dn.net/?f=%5Coverline%7BCD%7D%20%3D%2012%20%5C%3A%20units)
![\overline{C'D'}](https://tex.z-dn.net/?f=%5Coverline%7BC%27D%27%7D)
is the image of CD after a dilation of scale factor n.
We use the relation between the image length and object length:
![\overline{C'D'} = n \times \overline{CD}](https://tex.z-dn.net/?f=%5Coverline%7BC%27D%27%7D%20%3D%20n%20%5Ctimes%20%5Coverline%7BCD%7D)
Option A
If n=3/2, then
![\overline{C'D'} = \frac{3}{2} \times 12 = 3 \times 6 = 18 \: units](https://tex.z-dn.net/?f=%5Coverline%7BC%27D%27%7D%20%20%3D%20%20%5Cfrac%7B3%7D%7B2%7D%20%20%5Ctimes%2012%20%3D%203%20%5Ctimes%206%20%3D%2018%20%5C%3A%20units)
This is true.
Option B
If n=4, then
![\overline{C'D'} = 4 \times 12 = 36 \: units](https://tex.z-dn.net/?f=%20%5Coverline%7BC%27D%27%7D%20%3D%204%20%5Ctimes%2012%20%3D%2036%20%5C%3A%20units)
This is false.
Option C
If n=8, then
![\overline{C'D'} = 8 \times 12 = 96 \: units](https://tex.z-dn.net/?f=%20%5Coverline%7BC%27D%27%7D%20%3D%208%20%5Ctimes%2012%20%3D%2096%20%5C%3A%20units)
This too is false.
Option D
If n=2, then
![\overline{C'D'} = 2 \times 12 = 24 \: units](https://tex.z-dn.net/?f=%5Coverline%7BC%27D%27%7D%20%3D%202%20%5Ctimes%2012%20%3D%2024%20%5C%3A%20units)
This is true
Option E
If n=3/4, then
![\overline{C'D'} = \frac{3}{4} \times 12](https://tex.z-dn.net/?f=%5Coverline%7BC%27D%27%7D%20%3D%20%20%5Cfrac%7B3%7D%7B4%7D%20%20%5Ctimes%20%2012)
![\overline{C'D'} = 3 \times 3 = 9 \: units](https://tex.z-dn.net/?f=%5Coverline%7BC%27D%27%7D%20%3D%20%203%20%5Ctimes%203%20%3D%209%20%5C%3A%20units)
This is also true.
Answer:
1.C
2.A
Step-by-step explanation:
Answer:
9.7
Step-by-step explanation:
tan=opposite/adjacent
tan=9/adjacent
tan 43=9/x
x tan 43=9
0.9325x=9
0.9325x/0.9325=9/0.9325
=9.65
hence;
x=9.7
That is false the opposite of 7 is -7
The correct answer is B. 72 because you can multiply 3*6*4 to represent every combination possible.