The value of the angle ∠AVB is 53°, side VB = 132.83 m, side OV = 119 m
<h3>How to find the side length from bearings?</h3>
8) From the given triangle we see that;
∠VAO = 37°
∠VBO = 64°
∠VOA = 90°
a) Now, we know that sum of angles in a triangle is 180°. Thus, for triangle AVO, we can say that;
∠VAO + ∠VOA + ∠AVB = 180°
37 + 90 + ∠AVB = 180°
∠AVB = 180° - 127°
∠AVB = 53°
b) Using triangle rules we can say that;
tan 64 = VO/BO
Similarly, we can say that;
tan 37 = VO/(100 + BO)
Dividing both equations gives;
tan 64/tan 37 = (100 + BO)/BO
2.72BO = 100 + BO
1.72BO = 100
BO = 58.14 m
Using trigonometric ratio;
58.14/VB = cos 64
VB = 132.83 m
c) OV/132.83 = sin 64
OV = 132.83 * sin 64
OV = 119 m
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The answer is B.
complementary means adding upto 90 degrees, but they dont unless they're both 45 degrees, so its not A.
they are not supplementary because that means they add up to 180 degrees and they dont unless theyre both 90 degrees, so its not C.
there IS a relationship between the measures of corresponding angles, so its not D.
the relationship between them is that they are always the same, so the answer is B.
Answer:
the length of the ramp is 25 meters
Step-by-step explanation:
Joe is making a ramp. Ramp forms a right angle triangle with the base
So we use Pythagorean theorem to find the length of the ramp
AC^2(hypotenuse) = AB^2 + BC^2
Length of ramp is the hypotenuse = 
=
= 
= 
= 25
so the length of the ramp is 25 meters
Answer:
Adjust the compasses' width to the point Q. The compasses' width is now equal to the length of the line segment PQ.
Step-by-step explanation:
Start with a line segment PQ that we will copy. Mark a point R that will be one endpoint of the new line segment. Set the compasses' point on the point P of the line segment to be copied. Adjust the compasses' width to the point Q. The compasses' width is now equal to the length of the line segment PQ.
