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3 years ago

For the function f(t)+Pe^rt, if P = 8 and r = 0.08, then what is the value of f(8) to the nearest tenth?

Mathematics

2 answers:

Gelneren [198K]3 years ago

5 0

Answer:

The answer would be 15.2

Step-by-step explanation:

I just took the Quiz on APEX

Bogdan [553]3 years ago

4 0

F(t) = P.e^(r.t) [ and not as you wrote it f(t)+Pe^rt]
plug in:

f(t) = 8.e^(0.08t) (where e = 2.718 and t=8 given, f(8))
f(8) = 8.(2.718)^(0.08*8) = 21.74^(0.64)

f(8) = 7.17

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Step-by-step explanation:

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2 years ago

Evaluate the integral. (Use C for the constant of integration.) <br> cos(x) (8 + 7 sin^2(x)) dx

UNO [17]

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Step-by-step explanation:

Consider $\int \cos(x) (8+7 \sin^2(x)) \, dx$

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3 years ago