Answer: (x,y) = (1,6)
Step-by-step explanation:
Answer:
h(3) = - 140
Step-by-step explanation:
Generate the terms in the sequence by substituting n = 2 and 3 into h(n)
h(2) = h(2 - 1) × 2 = h(1) × 2 = - 35 × 2 = - 70
h(3) = h(3 - 1) × 2 = h(2) × 2 = - 70 × 2 = - 140
Answer:
The sweat chloride reference value is less than 30 mmol/L. A value of more than 60 mmol/L of chloride in the sweat is consistent with a diagnosis of cystic fibrosis. The values of 30-60 mEq/L may represent heterozygous carriers, these carriers cannot be accurately identified with a sweat chloride test.
The complete factorisation of 50a²b⁵ − 35a⁴b³ + 5a³b⁴ is 5a²b³(10b² - 7a² + ab)
<h3>How to factorise?</h3>
Factorisation is the process of writing an expression as a product of two or more common factors.
The expression is written as a product of several factor.
Therefore,
50a²b⁵ − 35a⁴b³ + 5a³b⁴
Hence, the complete factorisation is as follows;
5a²b³(10b² - 7a² + ab)
learn more on factorisation here: brainly.com/question/2272501
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