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adoni [48]
3 years ago
13

Use the graph to find the indicated function value y=f(x). Find f(-2)

Mathematics
1 answer:
spin [16.1K]3 years ago
7 0

Answer:

f(-2)=3

Step-by-step explanation:

we know that

f(-2) is the value of the function f(x) for the value of x equal to -2

so

Observing the graph

For x=-2

f(-2)=3

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Please help its easy just i'm dvmb, just need this for my homework real soon!.. DON'T MIND THOSE ANSWERS SELECTED!!!!
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<h3><em>Hey there today we will solve your problem,</em></h3>

Number 1

_______________

<h3>Definitions</h3>
  • Vertical angles - <em>either of two angles lying on opposite sides of two intersecting lines.</em>

<em />

  • Linear Pair - <em>A linear pair is a pair of adjacent angles formed when two lines intersect.</em>

_______________

Now we can solve Number 1, there is one pair of Vertical angles being ∠5 and ∠3

_______________

Number 2

Since we know the definition of a Linear Pair we can solve this problem also, the only Linear Pair that we can choose out the ones give to us is ∠4 and ∠3, because they are adjacent.

_______________

{\huge{\boxed{\mathfrak{Answer}}}

  1. ∠5 and ∠3

    2. ∠4 and ∠3

8 0
3 years ago
What is the y-intercept of this quadratic function f(x) = x^2 + 2x + 3 A. (0,1) B. (0,-1) C. (0,-3) D. (0,3)
Firdavs [7]

Answer:

d=(0,3)

Step-by-step explanation:

8 0
3 years ago
If AB=12 cm and BC =13 cm then AC = 25 cm
Maru [420]

Answer:

AB=12

Hope this helps!

8 0
2 years ago
Bonjour je ne comprend pas cette exercice; si quelqu'un peut m'aider je suis preneuse.
gayaneshka [121]

Answer:

0,24 m

Step-by-step explanation:

La table est un rectanble donc l'angle en  haut à droite est de 90°.

Tu connais donc un angle et le côté opposé à l'angle et tu cherche le côté adjacent.

On sait que tan(â) = \frac{Cote oppose}{Cote adjacent} donc :

tan(40)= \frac{1,27}{x}

\frac{1,27}{tan(40)} = x

donc x ≈ 1,51 m

Le trou du mileu est à \frac{2,54}{2} soit 1,27m du bord.

Donc elle doit taper à 1,51 - 1,27 = 0,24m du trou du milieu.

j'espère avoir été clair.

<h2 />
8 0
2 years ago
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