Question

Use slope-intercept form, y = mx + b, to find the value for the y-intercept (b) of a line that has a slope of 6 and passes through the point (3, –5).
b = (dropdown) –23, –14, 21, 33

What is the new equation written in slope-intercept form?
(dropdown) y = 6x – 23, y = 6x – 14, y = 6x + 21, y = 6x + 33

Answer 1

Answer:

-23, $y=6x-23$

Step-by-step explanation:

We need slope intercept form but do not have the needed information. We will gather this information by using point slope form. The point-slope formula is $y -y_{1} =m(x -x_{1})$ where we substitute a point (x,y) for $(x_{1},y_{1})$.  

We have slope represented as m=6 and (3, -5). We input m and $x_{1} =3\\y_{1}=-5$.

$y-(-5)=6(x-3)\\y+5=6(x-3)$

We now simplify the parenthesis and solve for y to have slope intercept form.

$y+5=6(x-3)\\y+5=6x-18\\y+5-5=6x-18-5\\y=6x-23$

The y-intercept is b of slope intercept form y=mx+b. Here b=-23.