Answer:
Ix = Iy = 
Radius of gyration x = y = 
Step-by-step explanation:
Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.
Mass of disk = ρπR2
Moment of inertia about its perpendicular axis is 
. Moment of inertia of quarter disk about its perpendicular is 
.
Now using perpendicular axis theorem, Ix = Iy = 
= .
For Radius of gyration K, equate MK2 = MR2/16, K= R/4.
Answer:
x = 0
Step-by-step explanation:
To 'solve' means to find the x values that make the equation equal zero, so
0 = (3x)/[(x + 5)(x - 4)
Multiply both sides by the denominator to get rid of the fraction
0[(x + 5)(x - 4)] = [(3x)(x + 5)(x - 4)]/[(x + 5)(x - 4)]
0 = 3x
0 = x (divide both sides by 3)
So x = 0 is the solution for this equation
Answer:
draw a right angle triangle
Step-by-step explanation:
Let one of the angles be A
cos A = sin (90-A)
90 - x - 20 = x
2x = 70
x = 35 degrees
Find the common denominator
It is 6
Multiply everything by 6
2/3*(6)= 4g
1/2 *(6)= 3g
14*(6)= 84
4g +3g = 84
7g= 84
g= 12
Answer:
4
Step-by-step explanation:
On a number line you will got to -8 and go up 12 and you would get 4
