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Karolina [17]
3 years ago
14

A cafeteria uses 556 kg of rice each week. The rice comes in bags that hold 13 kg each.

Mathematics
1 answer:
Ratling [72]3 years ago
5 0
42 bags of rice is what the cafeteria use each week.
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Use the interactive number line to find -3.2 - 4.
SVEN [57.7K]

Answer:

-7.2

Step-by-step explanation:

Since -3.2 is the first number, this will be the starting point in the number line.

Since we are subtracting, we are going to go 4 units to the left.

-3.2 - 4 = -7.2

Best of Luck!

6 0
3 years ago
Describe the pattern 2, 4, 9, 11, 16, 18, 23
s2008m [1.1K]
The pattern is 2+ and 5+
7 0
3 years ago
Read 2 more answers
I need help with this one because I got my answers wrong
cluponka [151]
40+60+y=180
y=180-100
y=80

A triangle is 180° so you add all the numbers available in the trianle and minus it with 180 to see what is left from the 180 and that will be the inner angle answer

X=180-80=100

A straight line is also 180° so if u minused one side which in our case is 80 u will get the rest which is the outer angle
7 0
3 years ago
Express the ratio in its simplest form 1\4:1\8:1\16​
HACTEHA [7]

Answer:

4 : 2: 1

Step-by-step explanation:

\frac{1}{4}   :  \frac{1}{8}  :  \frac{1}{16}  \\  \\ multiplying \: throughout \: by \: 16 \\  \\ 16 \times  \frac{1}{4}   :   \:16 \times \frac{1}{8}  :  \: 16 \times \frac{1}{16}  \\  \\ 4 : 2 : 1

6 0
3 years ago
Given segments AB and CD intersect at E.
nata0808 [166]

The length of a segment is the distance between its endpoints.

  • \mathbf{AB = 3\sqrt{2}}
  • AB and CD are not congruent
  • AB does not bisect CD
  • CD does not bisect AB

<u>(a) Length of AB</u>

We have:

\mathbf{A = (1,2)}

\mathbf{B = (4,5)}

The length of AB is calculated using the following distance formula

\mathbf{AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}

So, we have:

\mathbf{AB = \sqrt{(1 - 4)^2 + (2 - 5)^2}}

\mathbf{AB = \sqrt{18}}

Simplify

\mathbf{AB = 3\sqrt{2}}

<u>(b) Are AB and CD congruent</u>

First, we calculate the length of CD using:

\mathbf{CD = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}

Where:

\mathbf{C = (2, 4)}

\mathbf{D = (2, 1)}

So, we have:

\mathbf{CD = \sqrt{(2 -2)^2 + (4 - 1)^2}}

\mathbf{CD = \sqrt{9}}

\mathbf{CD = 3}

By comparison

\mathbf{CD \ne AB}

Hence, AB and CD are not congruent

<u>(c) AB bisects CD or not?</u>

If AB bisects CD, then:

\mathbf{AB = \frac 12 \times CD}

The above equation is not true, because:

\mathbf{3\sqrt 2 \ne \frac 12 \times 3}

Hence, AB does not bisect CD

<u>(d) CD bisects AB or not?</u>

If CD bisects AB, then:

\mathbf{CD = \frac 12 \times AB}

The above equation is not true, because:

\mathbf{3 \ne \frac 12 \times 3\sqrt 2}

Hence, CD does not bisect AB

Read more about lengths and bisections at:

brainly.com/question/20837270

7 0
3 years ago
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