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Sloan [31]
3 years ago
8

Which of the following are solutions to the inequality below? select all that apply

Mathematics
1 answer:
wariber [46]3 years ago
6 0
The answer is #1, #2, and #4

It’s #1 because if you look at a number line -3 is before -4

It’s #2 because it’s less then or equal to and -4 is equal to -4

And lastly it’s #4 because 3 is greater then -4

Hope this helps!!
You might be interested in
Fill in the gaps in the arithmetic sequence -3, _ ,_ , _, _, _ 12
lord [1]

Answer:

  -0.5, 2, 4.5, 7, 9.5

Step-by-step explanation:

The given terms are 6 apart, so the common difference is 1/6 of their difference:

  d = (12 -(-3))/6 = 15/6 = 5/2 = 2.5

Add 2.5 to each term to get the next one. Then the sequence is ...

  -3, <u>-0.5</u>, <u>2.0</u>, <u>4.5</u>, <u>7.0</u>, <u>9.5</u>, 12

8 0
4 years ago
0.0000005060 in scientific notation
marin [14]
3.6550000000051 × 10^5
7 0
3 years ago
10.) Part A: What is the area, in square feet, of the kitchen?
just olya [345]

The computation shows that the area of the kitchen that's in the home in square feet is 50ft².

<h3>How to calculate the area?</h3>

It should be noted that an area of a rectangular space is calculated by multiplying the length by the width.

In this case, the area of the kitchen will be:

= 5ft × 10ft

= 50ft²

Learn more about area on:

brainly.com/question/25292087

4 0
2 years ago
3) Find the length of a rectangular lot with a perimeter of 92 m if the length is 8 m more than
Nikolay [14]

Answer:

26 m

Step-by-step explanation:

Perimeter = 92 m

Length = 8 m more than width

Width: 20 m

Therefore,

<h2>length=26 m</h2>
4 0
4 years ago
A simple random sample of size nequals10 is obtained from a population with muequals68 and sigmaequals15. ​(a) What must be true
valentina_108 [34]

Answer:

(a) The distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b) The value of P(\bar X is 0.7642.

(c) The value of P(\bar X\geq 69.1) is 0.3670.

Step-by-step explanation:

A random sample of size <em>n</em> = 10 is selected from a population.

Let the population be made up of the random variable <em>X</em>.

The mean and standard deviation of <em>X</em> are:

\mu=68\\\sigma=15

(a)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Since the sample selected is not large, i.e. <em>n</em> = 10 < 30, for the distribution of the sample mean will be approximately normally distributed, the population from which the sample is selected must be normally distributed.

Then, the mean of the distribution of the sample mean is given by,

\mu_{\bar x}=\mu=68

And the standard deviation of the distribution of the sample mean is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{15}{\sqrt{10}}=4.74

Thus, the distribution of the sample mean (\bar x) is <em>N</em> (68, 4.74²).

(b)

Compute the value of P(\bar X as follows:

P(\bar X

                    =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the value of P(\bar X is 0.7642.

(c)

Compute the value of P(\bar X\geq 69.1) as follows:

Apply continuity correction as follows:

P(\bar X\geq 69.1)=P(\bar X> 69.1+0.5)

                    =P(\bar X>69.6)

                    =P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{69.6-68}{4.74})

                    =P(Z>0.34)\\=1-P(Z

Thus, the value of P(\bar X\geq 69.1) is 0.3670.

7 0
4 years ago
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