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SVETLANKA909090 [29]
4 years ago
8

6 minus twice a number is less than or equal to 100. What is the solution of the inequality?

Mathematics
1 answer:
anyanavicka [17]4 years ago
6 0
The solution would be 53. The inequality would be 2n - 6 /< (less than or equal to) 100. You would just add 6 to both sides and then divide each side by 2, giving you n = 53. Hopefully this helped and make sure to make this the brainliest answer :)
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Molly wants to pursue a graduate degree at New University but is unsure whether to specialize in law or medicine. To help her de
Mashutka [201]

Answer:

Molly's Z score for LSAT

z-score=-2

Molly's Z score for MCAT

z-score=2

Step-by-step explanation:

z-score for LSAT

Molly's score=120

mean=150

Standard deviation=15

z-score= (Molly LSAT score-mean)/standard deviation

z=120-150/15=-30/15=-2

z-score for MCAT

Molly's score=52

mean=40

Standard deviation=6

z-score= (Molly MCAT score-mean)/standard deviation

z=52-40/6=12/6=2

3 0
3 years ago
Caitlyn did 6/7 of the problems on her math correctly and 4 incorrectly. She did all the problems. How many were there?
Viefleur [7K]
If \frac{6}{7} were incorrect, it means that \frac{1}{7}=4 were correct
4*7=28
There were 28 problems ;)
5 0
3 years ago
What plus 150 equals to 180
zzz [600]

Answer:

30

Step-by-step explanation:

150+30=180

Hope This Helps!!

(brainliest please, if possible)

5 0
3 years ago
Read 2 more answers
What number complete the square x^2 +\- bx
kati45 [8]
Take 1/2 of b and squaer it so (b/2)^2 would complete the square (sign doesn't matter becaus when squareing, sign goes positive)
7 0
3 years ago
What are the potential solutions of In(x^2-25)=0?
Maslowich

Answer:

x =\pm \sqrt{26}

Step-by-step explanation:

<u>Given </u><u>:</u><u>-</u><u> </u>

  • ln ( x² - 25 ) = 0

And we need to find the potential solutions of it. The given equation is the logarithm of x² - 25 to the base e . e is Euler's Number here. So it can be written as ,

<u>Equation</u><u> </u><u>:</u><u>-</u><u> </u>

\implies log_e {(x^2-25)}= 0

<u>In </u><u>general</u><u> </u><u>:</u><u>-</u><u> </u>

  • If we have a logarithmic equation as ,

\implies log_a b = c

Then this can be written as ,

\implies a^c = b

In a similar way we can write the given equation as ,

\implies e^0 = x^2 - 25

  • Now also we know that a^0 = 1 Therefore , the equation becomes ,

\implies 1 = x^2 - 25 \\\\\implies x^2 = 25 + 1 \\\\\implies x^2 = 26 \\\\\implies x =\sqrt{26} \\\\\implies x = \pm \sqrt{ 26}

<u>Hence</u><u> the</u><u> </u><u>Solution</u><u> </u><u>of </u><u>the</u><u> given</u><u> equation</u><u> is</u><u> </u><u>±</u><u>√</u><u>2</u><u>6</u><u>.</u>

6 0
3 years ago
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