Question

a student is given a reading list of ten books from which he must select two for an outside reading requirement. in how many ways can he make his selection

Answer 1

Answer:

The ways in which he can make selection = $10\times 9 =90$

Step-by-step explanation:

Student is having a list of $10$ books.

Assuming that the student can't read the same book twice.

The student has $2$ choices to make for an outside reading requirement,for his 1st choice, he had $10$ books to choose from; for his 2nd, he has $9$ books left to choose from therefore the total permutations of his choices are $=10\times 9 =90$

So the total ways in which the student can make his selection = $90$