Do you have a photo or something?
Answer:
P / 30 - 21= 9
2w = 9
w = 4.5
This should be the answer
Answer:
67.5feet
Step-by-step explanation:
Given parameters:
Model distance between building and gymnasium = 22.5 inches
Scale of model : 1 inch = 3 feet
Unknown:
Actual ground distance = ?
To solve this problem, we first must understand the concept of scale. A scale is a relationship that represents a dimension on a map/model compared to the true ground expression. In order to visualize or represent some real life objects on paper or in a computer, we use models. These models are an abstraction of the real world based on scales. There are different ways of representing a scale.
In this problem;
the scale is given as;
1 inch on model represents 3 feet on ground
Now, to find 22.5 inches, simply cross multiply and solve;
If 1 inch on model represents 3 feet on ground
22.5 inches on a model will be = 
= 67.5feet
Therefore, the actual distance is 67.5feet
Answer:
m= 1/10
Step-by-step explanation:
1. Move the terms so that will be 3m - 2m=-1/2 + 3/5
2. Subtract the m values so that will be 3m - 2m= 1 or m
3. Calculate the sum.
4. So the answer will be m= 1/10. M because we subtracted 2 from 3 which make us 1 so we say it m and 1/10 by doing 1/2 + 3/5.
Fun fact
if f(a)=b then f⁻¹(b)=a
so
if f⁻¹(b)=a then f(a)=b
so we find f(x)=27 and the solve for x
f(x)=3x=27
3x=27
divide both sides by 3
x=9
so if f(9)=27 then f⁻¹(27)=9
problem solved
answer is 9