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olganol [36]
3 years ago
13

The arrow next to all programs indicates

Computers and Technology
1 answer:
myrzilka [38]3 years ago
6 0

Answer:

the presence of a submenu

Explanation:

The options are:

  • this item cannot be selected
  • that this was the most recently used item
  • the importance of the item
  • the presence of a submenu

And the correct option is certainly the fourth option, and which is the presence of the submenu. The arrow next to all the programs certainly indicates that there is a submenu, and hence, the fourth option is the correct option here.

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What is the purpose of reading in typography
IgorLugansk [536]

Answer:

The main purpose of typography is to make life easier for your readership by making it easier to read what you've written: It makes it possible to to quickly scan your text. It entices your readers to engage with your text. When done well, it enhances the message it presents

4 0
3 years ago
Is a computer an input output or storage
Effectus [21]

Answer:

Explanation:

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Excel solver is the only method that one can utilize for automated linear programming solutions. True or False
klasskru [66]

Answer:

False

Explanation:

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3 0
3 years ago
01110111 01101000 01100001 01110100 00100000 01101001 01110011 00100000 00110001 00101011 00110001
Lera25 [3.4K]
Same lol thesis so me right now
7 0
4 years ago
Consider a binary search tree where each tree node v has a field v.sum which stores the sum of all the keys in the subtree roote
AVprozaik [17]

Answer:

Each time you insert a new node, call the function to adjust the sum.

This method has to be called each time we insert new node to the tree since the sum at all the

parent nodes from the newly inserted node changes when we insert the node.

// toSumTree method will convert the tree into sum tree.

int toSumTree(struct node *node)

{

if(node == NULL)

return 0;

// Store the old value

int old_val = node->data;

// Recursively call for left and right subtrees and store the sum as new value of this node

node->data = toSumTree(node->left) + toSumTree(node->right);

// Return the sum of values of nodes in left and right subtrees and

// old_value of this node

return node->data + old_val;

}

This has the complexity of O(n).

Explanation:

6 0
3 years ago
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