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oksano4ka [1.4K]
3 years ago
8

Jessie has n dollars in his bank account. He deposits $132.00. Write an expression that represents the total amount Jessie now h

as in his account.
Mathematics
1 answer:
Kamila [148]3 years ago
8 0
N-$132.00=what he now has in account
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The volume of the cylinder above is 2,314.25, and the radius of the base is 8.9 Find the volume of the cone.
olga55 [171]

Answer: 771.41\ units^3

Step-by-step explanation:

The missing figure is attached.

The volume of an oblique cylinders and the volume of  a right cylinder can be found with this formula:

V_{cy}=\pi r^2h

Where "r" is the radius and "h" is the height.

The volume of an oblique cone and the volume of  a right cone can be found with this formula:

V_{co}=\frac{1}{3}\pi r^2h

Where "r" is the radius and "h" is the height.

According to the information given in the exercise, you know that the volume of the cylinder and also the radius of the cylinder and the cone ,are the following:

V_{cy}=2,314.25\ units^3\\\\r=8.9\ units

Therefore, in order to find the volume of the cone, you only need to multiply the volume of the cylinder by \frac{1}{3}.

Then, you get:

V_{co}=\frac{1}{3}(2,314.25\ units^3)\\\\V_{co}=771.41\ units^3

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What are the missing reasons in the two-column proof?
Nesterboy [21]

Reasons:

1. Because, MO cuts Angle PMN in two equal parts.

2.As ∠PMN is cut in to equal parts thus:

∠PMN = ∠NMO + ∠PMO, where these two parts (∠NMO, ∠PMO) are equal.

3. Both are the same, common you can say..

4. Because, MO cuts Angle PON in two equal parts.

5. As ∠PON is cut in to equal parts thus:

∠PON = ∠NOM + ∠POM, where these two parts (∠NOM , ∠POM) are equal.

6. From the above statements, we have:

= ∠NMO + ∠PMO (Proved)

= ∠NOM + ∠POM (Proved)

= MO = MO (Proved)

Thus, ∆PMO ≅ ∆NMO, by AAS rule

________________________________

As simpoool as that!

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3 years ago
Pls help! giving thanks. What is the slope of the line (picture above)
Nezavi [6.7K]

Answer:

slope = 1

Step-by-step explanation:

We can see that the graph cuts the x axis at , (-1,0) and y axis at (0,1) . So we can find the slope as ,

\implies slope = \dfrac{y_2-y_1}{x_2-x_1}\\\\\implies slope = \dfrac{ 1-0}{0+1} \\\\\implies\boxed{\boxed{ slope = 1 }}

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3 years ago
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