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oksano4ka [1.4K]

3 years ago

8

Jessie has n dollars in his bank account. He deposits $132.00. Write an expression that represents the total amount Jessie now h

as in his account.

1 answer:

Kamila [148]3 years ago

8 0

N-$132.00=what he now has in account

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Use the drawing tools to form the correct answer on the graph. Plot function f on the graph. f(x)= 3, -9

Butoxors [25]

The equation of the function f with solution 3, -9 is x²+6x-27 and the graph of this equation with the use of drawing tools is attached below.

<h3>What is the definition of a Function?</h3>

A function assigns the value of each element of one set to the other specific element of another set.

A function has to be plot which has the value of f(x) as 3 and -9. Here, 3 and -9 are the solution of the function. Thus,

x=3

x-3=0

The second solution is,

x=-9

x+9=0

Multiply both factor for the function as,

f(x)=(x-3)(x+9)

f(x)=x²+9x-3x-27

f(x)=x²+6x-27

This is the required function. The graph of this function is attached below.

Thus, the equation of the function f with solution 3, -9 is x²+6x-27 and the graph of this equation with the use of drawing tools is attached below.

Learn more about Function here:

brainly.com/question/5245372

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2 years ago

The Grade 8 learners decided to start living more healthily. They will either jog or cycle.

liberstina [14]

Step-by-step explanation:

(125/5)×3=75

75 participate jogging

25×2=50

50 participate in cycling

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3 years ago

Six ounces of a nutrition shake provides 2 grams of protein. Will 24 ounces of the drink provide 10 grams of protein? Explain

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Answer:

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Step-by-step explanation:

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7 0

2 years ago

A virus strain is 0.00000015 meters in length. What is the length in scientific notation?

yulyashka [42]

Answer:

1.5*10^-5

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

If dy dx equals cosine squared of the quantity pi times y over 4 and y = 1 when x = 0, then find the value of x when y = 3.

Afina-wow [57]

Answer: $x = -\frac{8}{\pi}$

Explanation: Note that

$\frac{dy}{dx} = \cos^2 \left ( \frac{\pi y}{4} \right )
\\
\\ \frac{dy}{\cos^2 \left ( \frac{\pi y}{4} \right )} = dx
\\
\\ \int{\frac{dy}{\cos^2 \left ( \frac{\pi y}{4} \right )}} = \int dx
\\
\\ \boxed{x = \int{\sec^2 \left ( \frac{\pi y}{4} \right )dy}}$

To evaluate the integral in the boxed equation, let $u = \frac{\pi y}{4}$ . Then,

$du = \frac{\pi}{4} dy 
\\ \Rightarrow \boxed{dy = \frac{4}{\pi}du}$

So,

$x = \int{\sec^2 \left ( \frac{\pi y}{4} \right )dy}
\\
\\ = \int{\sec^2 u \left ( \frac{4}{\pi}du \right )}
\\
\\ = \frac{4}{\pi}\int{\sec^2 u du}
\\
\\ = \frac{4}{\pi} \tan u + C
\\
\\ \boxed{x = \frac{4}{\pi} \tan \left ( \frac{\pi y}{4} \right ) + C}\text{ (1)}$

Since y = 1 when x =0, equation (1) becomes

$0 = \frac{4}{\pi} \tan \left ( \frac{\pi (1)}{4} \right ) + C 
\\ 
\\ 0 = \frac{4}{\pi} (1) + C 
\\
\\ \frac{4}{\pi} + C = 0
\\
\\ \boxed{C = -\frac{4}{\pi}}$

With the value of C, equation (1) becomes

$\boxed{x = \frac{4}{\pi} \tan \left ( \frac{\pi y}{4} \right ) -\frac{4}{\pi} }$

Hence, if y = 3,

$x = \frac{4}{\pi} \tan \left ( \frac{\pi y}{4} \right ) -\frac{4}{\pi} 
\\
\\ x = \frac{4}{\pi} \tan \left ( \frac{\pi (3)}{4} \right ) -\frac{4}{\pi} 
\\
\\ x = \frac{4}{\pi} (-1) -\frac{4}{\pi} 
\\
\\ \boxed{x = -\frac{8}{\pi}}$

6 0

3 years ago