3 years ago

Find the value of c that makes each trinomial a perfect square. x^2-13x+c

Mathematics

1 answer:

vova2212 [387]3 years ago

8 0

Answer:

169/4

Step-by-step explanation:

x² - 13x + c

x² -2(x)(13/2) +(13/2)²

(13/2)² = 169/4 or 42 ¼

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So, we have:

$\mathbf{x \times y}$

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So, we have

$\mathbf{(x +1) \times (y -1) = 6 + xy }$

Open brackets

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There are several integers that fit the above <em>description</em>;

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