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Anna11 [10]
3 years ago
14

Tennis balls cost $7 for a can of 3. Steve gives the cashier $40 t to balls and receives $12 in change. How many tennis ball did

Steve buy?
Mathematics
2 answers:
lord [1]3 years ago
6 0
First, do  40 - 12 = 28 (Subtract the change), then do 28 / 7 to get 4, so then we do the cans times 3 to see how many individual balls he has, which would be 12
baherus [9]3 years ago
4 0
If you subtract 12 from 40, you get 40 - 12 = 28. So, Steve spent $28. Then, you divide 28 by 7. When you do 28/7 you get 4. This means that Steve bought 4 cans of tennis balls. Then, to find the total number of tennis balls purchased, you must multiply the number of cans purchased (4) by the number of balls in each can (3). So, when you do 4 x 3 you get 12. This mean that Steve bought a total of 12 tennis balls.
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olga nikolaevna [1]
Percent change = ((new value) - (old value))/(old value) × 100%
  = (180 -135)/135 × 100%
  = 33 1/3%

180 is about 33% greater than 135.
8 0
3 years ago
Help!! Answer !!! about to run out of time in test!!
Gemiola [76]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

Here's the solution ~

Let's find the measure of hypotenuse first, by using Pythagoras theorem ;

\qquad \sf  \dashrightarrow \: h {}^{2}  =  {8}^{2}  +  {6}^{2}

\qquad \sf  \dashrightarrow \: h {}^{2}  =  {36}^{}  +  {64}^{}

\qquad \sf  \dashrightarrow \: h {}^{2}  = 100

\qquad \sf  \dashrightarrow \: h {}^{}  =  \sqrt{100}

\qquad \sf  \dashrightarrow \: h {}^{}  =  {10}

Now, let's find the asked values ~

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{opposite \: side}{hypotenuse}

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{6}{10}

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{3}{5}   \: or \: 0.6 \: units

For Cos y :

\qquad \sf  \dashrightarrow \:  \cos(y) =  \dfrac{adjcant \: side}{hypotenuse}

\qquad \sf  \dashrightarrow \:  \cos(y)   = \dfrac{6}{10}

\qquad \sf  \dashrightarrow \:  \cos(y)   = \dfrac{3}{5}  \: or \: 0.6 \: units

As we can see that both sin x and Cos y have equal values, therefore The required relationships is equality.

I.e Sin x = Cos y

Hope it helps ~

3 0
3 years ago
Gareth 30 students in a class and the ratio of boys to girls in the class is 2:3 calculate the number of goals
pishuonlain [190]

Answer:

<em>There are 12 boys and 18 girls</em>

Step-by-step explanation:

<u>Equations</u>

There are 30 students in a class. Let's call:

x = number of boys

Since the sum of boys and girls is 30:

30 - x = number of girls

The ratio of boys to girls is 2:3, thus:

\displaystyle \frac{x}{30-x}=\frac{2}{3}

Crossing denominators:

3x = 2(30 - x)

Operating the parentheses:

3x = 60 - 2x

Adding 2x:

5x = 60

Dividing by 5:

x = 60/5 = 12

x = 12

There are 12 boys and 30-12=18 girls

8 0
3 years ago
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kozerog [31]
2

42 ÷ 2 = 21
16 ÷ 2 = 8

Let's try the other factors of 42...

42 ÷ 6 = 7
16 ÷ 6 = 2.66
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No...

42 ÷ 14 = 3
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7 0
3 years ago
For the equation given below, evaluate y′ at the point (−2,−1).<br><br> 3xy−3x−12=0.
SSSSS [86.1K]

Answer:

Y'=3xy-3x-12

Y'=F(-2,-1)=0

Step-by-step explanation:

The function of the equation at the point (-2,-1)

is where the equation make the function go to zero:

Y'=3xy-3x-12

Y'=F(-2,-1)=[3(-2)(-1)]-[3(-1)]-12

F(-2,-1)=[6]-[-6]-12

F(-2,-1)=6+6-12

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Solving for y

3xy-3x-12=0

y=4/x+x

Making y=0

\frac{4}{x}+x=0

x^{2} =-4

x=-2

So the values make the function go to zero

3 0
3 years ago
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