Three times the variable m minus four is equal to fourteen.
Another way could be:
Four less than three multiplied by m is equivalent to fourteen.
The first way I put it is simpler but if you really want to impress your teacher then I suggest going with the second way.
Also if you are looking to solve the equation then it would be:
3m - 4 = 14
+4 +4
------------
3m = 18
----- -----
3 3
m = 5
Hope that helped :-)
Answer:
(s*t)(-7) = 987
Step-by-step explanation:
s(x) = 2 - x²
t(x) = 3x
To find (s*t)(x), multiply s(x) and t(x).
(s*t)(x) = (2 - x²)(3x)
(s*t)(x) = 6x - 3x³
Now that you have (s*t)(x), plug -7 in.
(s*t)(-7) = 6(-7) - 3(-7)³
(s*t)(-7) = 6(-7) - 3(-343)
(s*t)(-7) = -42 + 1029
(s*t)(-7) = 987
M= -4/3
y=mx+b
y=(-4/3)x+b
5=(-4/3)*3 +b
b= 9
y=(-4/3)x+9
Step-by-step explanation:
16.................................................
<h3>Given</h3>
- Equation ax² + bx + c = 0
- One of the roots is twice the other
<h3>To find</h3>
<h3>Solution</h3>
Let the roots be p and q
<u>The sum and product of the roots:</u>
<u>The sum of the roots, considering p = 2q,</u>
And
<u>The product of the roots, considering p = 2q:</u>
And
<u>Substitute q with -b/(3a)</u>
- 2(-b/(3a))² = c/a
- 2b²/(9a²) = c/a
- 2b² = 9a²(c/a)
- 2b² = 9ac
=================================================
17. .................................................
<h3>Given</h3>
Quadratic equation
- ax² = bx + c = 0, with equal roots
<h3>To find</h3>
<h3>Solution</h3>
<u>Equal roots means the discriminant is zero:</u>
- D = √b² - 4ac
- √b² - 4ac = 0
- b² - 4ac = 0
- b² = 4ac
I hope this helps you out. It is very tedious
