All categories

3 years ago

Martiza is playing a computer game to help her learn about science. Her scores for six games were 11, 12,10,8,14, and 15

Mathematics

1 answer:

nordsb [41]3 years ago

8 0

Answer:

Points she needs to earn on the next game = 14

Step-by-step explanation:

Martiza scores for six games were 11, 12,10,8,14, and 15.

(11+12+10+8+14+15+x)/7=12

(70+x)/7 = 12

Multiply both sides by 7

(70+x)/7 *7 = 12*7

70+x = 84

Combine the constants:

x=84-70

x = 14

Points she needs to earn on the next game = 14....

You might be interested in

You are constructing a concrete landing pad for a helicopter. You have 4704 cubic feet of concrete

Sonja [21]

Answer:

Round it to the nearest hundredth

Step-by-step explanation:

6 0

3 years ago

Create a matrix that is equal to F+G. The first matrix below is named F and the second matrix below is named G. Name the new mat

likoan [24]

F+G:

$F+G=\begin{bmatrix}{-1.8} & {-8.6} & {} \\ {2.85} & {-1.4} & {} \\ {-1.8} & {5.1} & {}\end{bmatrix}+\begin{bmatrix}{1.32} & {-1.9} & {} \\ {2.25} & {0.0} & {} \\ {-6.2} & {1.4} & {}\end{bmatrix}$

Then, add the elements that occupy the same position:

$H=\begin{bmatrix}{-1.8+1.32} & {-8.6+(-1.9)} & {} \\ {2.85+2.25} & {-1.4+0.0} & {} \\ {-1.8+(-6.2)} & {5.1+1.4} & {}\end{bmatrix}$

Solve

$H=\begin{bmatrix}{-0.48} & {-10.5} & {} \\ {5.1} & {-1.4} & {} \\ {-8} & {6.5} & {}\end{bmatrix}$

So, we find the element at address h31:

$H=\begin{bmatrix}{h11} & {h12} & {} \\ {h21} & {h22} & {} \\ {h31} & {h32} & {}\end{bmatrix}$

In this case, position h31 is - 8.0

8 0

1 year ago

Confused on number 10. I put one solution, but I don’t know if it’s right. I got

velikii [3]

4(3x + 12) = -6(-8-2x)
12x + 48 = 48 +12x
12x + 18 = 12x + 48
0 = 0
answer is A. infinitely many solutions

4 0

3 years ago

Which fraction equals 4?

Ilya [14]

Answer: 8/2

Step-by-step explanation:

7 0

3 years ago

El peso total de los paquetes de arcilla es de

timofeeve [1]

<h3>No hay otra información sobre cómo se supone que debemos encontrar el peso total de los paquetes.</h3><h3 />

Publique una pregunta adecuada y puedo ayudar

7 0

3 years ago